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(a)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction: An organic compound in which carboxy
In order to give the name to the carboxylic acid group, the following steps are followed:
1. The parent (longest)
2. The ending of the parent chain from alkane (-e) is changed to -oic acid for a carboxylic acid group.
3. The numbering is of the chain is done in such a way that carbonyl carbon gets the smaller number.
4. Name should be written in alphabetical order and other substituents are shown by the number.
For number of carbons atoms chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(b)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction: An organic compound in which carboxy functional group that is -COOH is bonded to the carbon atom is said to be a carboxylic acid. The general formula for carboxylic acid is RCOOH or RCO2H. When -H of the carboxylic acid is replaced by an alkyl or aryl group (-R’) then it results in the formation of an ester having general formula RCOOR’.
The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.
So, in order to give the IUPAC name to the esters, the following steps are followed:
- The alkyl substituent from the alcohol is named first.
- The name of the parent chain from carboxylic acid part is replaced as carboxylate.
In order to write the common name of the esters, the common of acids are written from which the ester has been formed.
(c)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction: An organic compound in which carboxy functional group that is -COOH is bonded to the carbon atom is said to be a carboxylic acid. The general formula for carboxylic acid is RCOOH or RCO2H. When -H of the carboxylic acid is replaced by an alkyl or aryl group (-R’) then it results in the formation of an ester having general formula RCOOR’.
The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.
So, in order to give the IUPAC name to the esters, the following steps are followed:
- The alkyl substituent from the alcohol is named first.
- The name of the parent chain from carboxylic acid part is replaced as carboxylate.
In order to write the common name of the esters, the common of acids are written from which the ester has been formed.
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Chapter 17 Solutions
EBK BASIC CHEMISTRY
- The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;arrow_forwardThe highest boiling compound from among the following isA. 2-methylheptane; B. 3-methylheptane; C. 2,2-dimethylhexane;D. octane; E. 2,2,3-trimethylpentanearrow_forwardWhich of the following features are found in the most stable structure ofCH5NO that does not have a CO bond?w. a π bond, x. two NH bonds, y. one OH bond, z. 3 lone pairsA. w, x; B. x, y; C. y, z; D. x, y, z; E. all of them.arrow_forward
- Which one of the following functional groups is not present in thecompound shownA. amine; B. aldehyde, C. ether; D. amide. E. ketonearrow_forwardWhich of the following formulas correspond to at least one compound inwhich resonance is important?w. C2H5N x. C3H5Br; y. C3H4; z. C4H6.A. w, x, y; B. x, y, z; C. w, x, z; D. w, y, z; E. all of themarrow_forwardPredict the product(s) that are formed after each step for reactions 1-4. In each case, consider formation of any chiral center(s) and draw all expected stereoisomers. 1) OH 1) HBr (SN2) 2) NaOH, heat 3) BH3, THF 4) H2O2, NaOH 2) OH 1) SOCI 2, py 2) NaOEt 3) Br2, H₂O 3) OH 1) H2SO4 conc. 2) HBr, ROOR 3) KOtBu 4) OH 1) TsCl, py 2) NaOEt 3) 03 4) DMSarrow_forward
- Which of the following rings has the least strain in its most stableconformation?A. Cyclobutane; B. Cyclopentane; C. Cyclohexane; D. Cycloheptane;E. Cyclooctanearrow_forwardThe number of different carbon skeletons that have a main chain of 9carbons and an ethyl branch isA 3; B. 4; C. 5; D. 6; E. 7arrow_forwardQ5: Classify the following pair of molecules as constitutional isomers, enantiomers, diastereomers, the same molecule, or completely different molecules. Br O CI Br OH OH 111 Br .!!!/Br F OH and ...m Br Br OH CI Br OH ་་་་་" ། ་arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
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