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Concept explainers
(a)
Interpretation: The boiling point of an aqueous solution which has freezing point as -2.79°C needs to be determined.
Concept Introduction: Colligative properties are the properties of solution which depend on the number of particles present in the solution. Some common examples of colligative properties are depression in freezing point, elevation in boiling point, osmotic pressure, lowering in vapor pressure, etc. The number of particles is shown with the help of Van’t Hoff factor ‘i’.
The mathematical expression for depression in freezing point and elevation in boiling point are as given below:
(b)
Interpretation: Thevapor pressure of solution at 25°C needs to be determined, if the vapor pressure of pure water is 23.76 mmHg at same temperature.
Concept Introduction:When a non-volatile solute is dissolve in solvent to get solution the vapor pressure decreases for the solution and it can be calculated with the help of Raoult’s law that states that the vapor pressure of solution is the product of mole fraction of solvent and vapor pressure of pure solvent. When a volatile solute is added to the solvent, the overall vapor pressure of solution will be the sum of vapor pressure contribution of individual component.
The mathematical expression can be written as:
(c)
Interpretation: The assumption made to calculate vapor pressure and boiling point of solution needs to be determined.
Concept Introduction:When a non-volatile solute is dissolve in solvent to get solution the vapor pressure decreases for the solution and it can be calculated with the help of Raoult’s law that states that the vapor pressure of solution is the product of mole fraction of solvent and vapor pressure of pure solvent. When a volatile solute is added to the solvent, the overall vapor pressure of solution will be the sum of vapor pressure contribution of individual component.
The mathematical expression can be written as:
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Chapter 17 Solutions
EBK CHEMICAL PRINCIPLES
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
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- 30.0 mL of 0.10 mol/L iron sulfate and 20.0 mL of 0.05 mol/L of silver nitrate solutions are mixed together. Justify if any precipitate would formarrow_forwardDoes the carbonyl group first react with the ethylene glycol, in an intermolecular reaction, or with the end alcohol, in an intramolecular reaction, to form a hemiacetal? Why does it react with the alcohol it does first rather than the other one? Please do not use an AI answer.arrow_forwardThe number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forward
- Nonearrow_forwardThe number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forwardThe azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forward
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