
Starting Out with C++ from Control Structures to Objects (8th Edition)
8th Edition
ISBN: 9780133769395
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 17, Problem 12PC
Program Plan Intro
Double Merge
Program Plan:
“NumberList.h”:
- Include the required specifications into the program.
- Define a class named “NumberList”.
- Declare the member variables “value” and “*next” in structure named “ListNode”.
- Declare the constructor, copy constructor, destructor, and member functions in the class.
“NumberList.cpp”:
- Include the required header files into the program.
- Define a function named “appendNode()” to insert the node at end of the list.
- Declare the structure pointer variables “newNode” and “nodePtr” for the structure named “ListNode”.
- Assign the value of received variable “num” into “newNode” and assign the “newNode” address into null.
- Using “if…else” condition check whether the list is empty or not, if the “head” is empty and make a new node into “head” pointer. Otherwise, make a loop find last node in the loop.
- Assign “newNode” into the variable “nodePtr” value.
- Define a function named “displayList()” to print the values in the list.
- Declare the structure pointer “nodePtr” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Make a loop “while” to display the values of the list.
- Define a function named “insertNode()” used to insert a value into the list.
- Declare the structure pointer variables “newNode”, “dataPtr”, and “prev” for the structure named “ListNode”.
- Make a “newNode” value into the received variable value “num”.
- Using “if…else” condition to check whether the list is empty or not.
- If the list is empty, initialize a value into “head” pointer with the value of “newNode” variable.
- Otherwise, make a “while” loop to test the “num” value is less than the list values.
- Using “if…else” condition to initialize the value into list.
- Define a function named “deleteNode()” to delete a value from the list.
- Declare the structure pointer variables “nodePtr”, and “previousNode” for the structure named “ListNode”.
- Using “if…else” condition to check the “head” value equal to “num”.
- Initialize the address of “nodePtr” to the “head”.
- Remove the value using “delete” operator and reassign the “head” value into the “nodePtr”.
- If the “num” value not equal to the “head” value, define the “while” loop to assign the “nodePtr” into “previousNode”.
- Using “if” condition to delete the “previousNode” pointer.
- Define a destructor named “~NumberList()” to destroy the list values from the memory.
- Declare the structure pointer variables “nodePtr”, and “nextNode” for the structure named “ListNode”.
- Initialize the “head” value into the “nodePtr”.
- Define a “while” loop to make the links of node into “nextNode” and remove the node using “delete” operator.
- Define a member function named “mergeArray()” to merge the array into list.
- Using “for” loop to insert a value of the array into list.
- Make a call to “insertNode()” function to insert an index value of received array “dArray” into list.
“main.cpp”:
- Include the required header files into the program.
- Declare a constant variable “n” and initialize a value as “5”.
- Declare and define a variable “arr” in type of array.
- Make an object named “obj” for the class “NumberList” and call the member functions “append()” and “display()” using the object.
- Make a call to “mergeArray()” with arguments of “arr” and “n” and then print the list using “displayList()” function.
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
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Chapter 17 Solutions
Starting Out with C++ from Control Structures to Objects (8th Edition)
Ch. 17.1 - Prob. 17.1CPCh. 17.1 - Prob. 17.2CPCh. 17.1 - Prob. 17.3CPCh. 17.1 - Prob. 17.4CPCh. 17.2 - Prob. 17.5CPCh. 17.2 - Prob. 17.6CPCh. 17.2 - Prob. 17.7CPCh. 17.2 - Prob. 17.8CPCh. 17.2 - Prob. 17.9CPCh. 17.2 - Prob. 17.10CP
Ch. 17 - Prob. 1RQECh. 17 - Prob. 2RQECh. 17 - Prob. 3RQECh. 17 - Prob. 4RQECh. 17 - Prob. 5RQECh. 17 - Prob. 6RQECh. 17 - Prob. 7RQECh. 17 - Prob. 8RQECh. 17 - Prob. 9RQECh. 17 - Prob. 10RQECh. 17 - Prob. 11RQECh. 17 - Prob. 13RQECh. 17 - Prob. 14RQECh. 17 - Prob. 15RQECh. 17 - Prob. 16RQECh. 17 - Prob. 17RQECh. 17 - Prob. 18RQECh. 17 - Prob. 19RQECh. 17 - Prob. 20RQECh. 17 - Prob. 21RQECh. 17 - Prob. 22RQECh. 17 - Prob. 23RQECh. 17 - Prob. 24RQECh. 17 - Prob. 25RQECh. 17 - T F The programmer must know in advance how many...Ch. 17 - T F It is not necessary for each node in a linked...Ch. 17 - Prob. 28RQECh. 17 - Prob. 29RQECh. 17 - Prob. 30RQECh. 17 - Prob. 31RQECh. 17 - Prob. 32RQECh. 17 - Prob. 33RQECh. 17 - Prob. 34RQECh. 17 - Prob. 35RQECh. 17 - Prob. 1PCCh. 17 - Prob. 2PCCh. 17 - Prob. 3PCCh. 17 - Prob. 4PCCh. 17 - Prob. 5PCCh. 17 - Prob. 6PCCh. 17 - Prob. 7PCCh. 17 - List Template Create a list class template based...Ch. 17 - Prob. 9PCCh. 17 - Prob. 10PCCh. 17 - Prob. 11PCCh. 17 - Prob. 12PCCh. 17 - Prob. 13PCCh. 17 - Prob. 14PCCh. 17 - Prob. 15PC
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