CHEMISTRY  MOLECULAR NATURE OF MATTER
CHEMISTRY MOLECULAR NATURE OF MATTER
9th Edition
ISBN: 9781266177835
Author: SILBERBERG
Publisher: MCG
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Chapter 16.6, Problem 16.12BFP

(a)

Interpretation Introduction

Interpretation : The intermediate needs to interpret the given mechanism of the reaction of NO(aq)  with H2(g) .

  2NO(aq) N2O2(g)N2O2(g)+H2(g)N2O(g)+ H2O(g)N2O(g)+H2(g)N2(g)+H2O(g)

Concept Introduction :

Chemical kinetics is the branch of chemistry that deals with the rate of chemical reaction. The rate law is the expression of the active masses of the reactants involved in the chemical reaction. The rate constant is a proportionality constant between the rate and active mass of the reactant. The overall reactant can be the sum of the elementary steps of the chemical equations.

(b)

Interpretation Introduction

Interpretation : The consistency of the given mechanism must be interpreted with the given rate law.

  Rate=kNO(aq)2H2(g)

  2NO(aq) N2O2(g)N2O2(g)+H2(g)N2O(g)+ H2O(g)N2O(g)+H2(g)N2(g)+H2O(g)

Concept Introduction :

Chemical kinetics is the branch of chemistry that deals with the rate of chemical reaction. The rate law is the expression of the active masses of the reactants involved in the chemical reaction. The rate constant is a proportionality constant between the rate and active mass of the reactant. The overall reactant can be the sum of the elementary steps of the chemical equations.

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Chapter 16 Solutions

CHEMISTRY MOLECULAR NATURE OF MATTER

Ch. 16.4 - Substance X (black) changes to substance Y (red)...Ch. 16.4 - Prob. 16.6BFPCh. 16.4 - Prob. 16.7AFPCh. 16.4 - Prob. 16.7BFPCh. 16.4 - Prob. 16.8AFPCh. 16.4 - Prob. 16.8BFPCh. 16.5 - Prob. 16.9AFPCh. 16.5 - Prob. 16.9BFPCh. 16.5 - Prob. 16.10AFPCh. 16.5 - Prob. 16.10BFPCh. 16.6 - Prob. 16.11AFPCh. 16.6 - Prob. 16.11BFPCh. 16.6 - Prob. 16.12AFPCh. 16.6 - Prob. 16.12BFPCh. 16.7 - Prob. 16.1PCh. 16.7 - Aircraft in the stratosphere release NO, which...Ch. 16.7 - Prob. 16.3PCh. 16 - Prob. 16.1PCh. 16 - Prob. 16.2PCh. 16 - A reaction is carried out with water as the...Ch. 16 - Prob. 16.4PCh. 16 - Prob. 16.5PCh. 16 - Prob. 16.6PCh. 16 - Prob. 16.7PCh. 16 - Prob. 16.8PCh. 16 - Prob. 16.9PCh. 16 - Prob. 16.10PCh. 16 - Prob. 16.11PCh. 16 - Prob. 16.12PCh. 16 - Prob. 16.13PCh. 16 - Prob. 16.14PCh. 16 - Prob. 16.15PCh. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Prob. 16.18PCh. 16 - Prob. 16.19PCh. 16 - Prob. 16.20PCh. 16 - Prob. 16.21PCh. 16 - Prob. 16.22PCh. 16 - Prob. 16.23PCh. 16 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Prob. 16.26PCh. 16 - Prob. 16.27PCh. 16 - Prob. 16.28PCh. 16 - By what factor does the rate in Problem 16.27...Ch. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - Prob. 16.35PCh. 16 - Prob. 16.36PCh. 16 - Give the overall reaction order that corresponds...Ch. 16 - Phosgene is a toxic gas prepared by the reaction...Ch. 16 - How are integrated rate laws used to determine...Ch. 16 - Define the half-life of a reaction. Explain on the...Ch. 16 - Prob. 16.41PCh. 16 - Prob. 16.42PCh. 16 - The first-order rate constant for the reaction A...Ch. 16 - The molecular scenes below represent the...Ch. 16 - In a first-order decomposition reaction, 50.0% of...Ch. 16 - A decomposition reaction has a rate constant of...Ch. 16 - Prob. 16.47PCh. 16 - Prob. 16.48PCh. 16 - In a study of ammonia production, an industrial...Ch. 16 - Prob. 16.50PCh. 16 - Prob. 16.51PCh. 16 - Prob. 16.52PCh. 16 - Prob. 16.53PCh. 16 - Prob. 16.54PCh. 16 - Prob. 16.55PCh. 16 - Prob. 16.56PCh. 16 - Prob. 16.57PCh. 16 - Assuming the activation energies are equal, which...Ch. 16 - For the reaction A(g) + B(g) ⟶AB(g), how many...Ch. 16 - Prob. 16.60PCh. 16 - Prob. 16.61PCh. 16 - For the reaction A2 + B2 → 2AB, Ea(fwd) = 125...Ch. 16 - Prob. 16.63PCh. 16 - Prob. 16.64PCh. 16 - The rate constant of a reaction is 4.7×10−3 s−1 at...Ch. 16 - The rate constant of a reaction is 4.50×10−5...Ch. 16 - Prob. 16.67PCh. 16 - Prob. 16.68PCh. 16 - Prob. 16.69PCh. 16 - Explain why the coefficients of an elementary step...Ch. 16 - Is it possible for more than one mechanism to be...Ch. 16 - What is the difference between a reaction...Ch. 16 - Why is a bimolecular step more reasonable...Ch. 16 - Prob. 16.74PCh. 16 - If a fast step precedes a slow step in a two-step...Ch. 16 - Prob. 16.76PCh. 16 - Prob. 16.77PCh. 16 - In a study of nitrosyl halides, a chemist proposes...Ch. 16 - Prob. 16.79PCh. 16 - Consider the reaction . Does the gold catalyst...Ch. 16 - Does a catalyst increase reaction rate by the same...Ch. 16 - In a classroom demonstration, hydrogen gas and...Ch. 16 - Prob. 16.83PCh. 16 - Prob. 16.84PCh. 16 - Prob. 16.85PCh. 16 - Consider the following reaction energy...Ch. 16 - Prob. 16.87PCh. 16 - Prob. 16.88PCh. 16 - A slightly bruised apple will rot extensively in...Ch. 16 - Prob. 16.90PCh. 16 - Prob. 16.91PCh. 16 - Prob. 16.92PCh. 16 - Prob. 16.93PCh. 16 - The citric acid cycle is the central reaction...Ch. 16 - Prob. 16.95PCh. 16 - Prob. 16.96PCh. 16 - Prob. 16.97PCh. 16 - Prob. 16.98PCh. 16 - For the reaction A(g) + B(g) ⟶ AB(g), the rate is...Ch. 16 - The acid-catalyzed hydrolysis of sucrose occurs by...Ch. 16 - At body temperature (37°C), the rate constant of...Ch. 16 - Is each of these statements true? If not, explain...Ch. 16 - Prob. 16.103PCh. 16 - Suggest an experimental method for measuring the...Ch. 16 - Prob. 16.105PCh. 16 - Many drugs decompose in blood by a first-order...Ch. 16 - Prob. 16.107PCh. 16 - Prob. 16.108PCh. 16 - Prob. 16.109PCh. 16 - Prob. 16.110PCh. 16 - Prob. 16.111PCh. 16 - Prob. 16.112PCh. 16 - Prob. 16.113PCh. 16 - Prob. 16.114PCh. 16 - Prob. 16.115PCh. 16 - Prob. 16.116PCh. 16 - Prob. 16.117PCh. 16 - Prob. 16.118PCh. 16 - The growth of Pseudomonas bacteria is modeled as a...Ch. 16 - Prob. 16.120PCh. 16 - Prob. 16.121PCh. 16 - Prob. 16.122PCh. 16 - Prob. 16.123PCh. 16 - Prob. 16.124PCh. 16 - Prob. 16.125PCh. 16 - Human liver enzymes catalyze the degradation of...Ch. 16 - Prob. 16.127PCh. 16 - Prob. 16.128P
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Kinetics: Initial Rates and Integrated Rate Laws; Author: Professor Dave Explains;https://www.youtube.com/watch?v=wYqQCojggyM;License: Standard YouTube License, CC-BY