Chapter 16.5, Problem 16.10BFP

Interpretation Introduction

Interpretation : The temperature at which the rate will be twice for the decomposition reaction should be interpreted if $E_{\text{a}}$ is $\text{1}\text{.14 }\times {\text{10}}^{\text{5}}\text{ J/mol}$ and the rate constant at $\text{500 K}$ is $\text{7}\text{.02}\times {10}^{-3}\text{ L/mol}\text{.s}$

  ${\text{2NO}}_{\text{2}}\text{(g)}\to \text{2NO(g)}+{\text{O}}_{\text{2}}\text{(g)}$

Concept Introduction : A catalyst is a substance that increases the rate of reaction without consuming overall during the reaction. It decreases the activation energy of the reaction so the reaction will be complete in less time. The activation energy is the minimum amount of energy that is needed to change the reactant molecule to product molecules. The relation between activation energy, rate constant, and temperature can be written as:

  $k=A{e}^{-E_a/RT}$

Here:

• $k$ = rate constant
• $A$ = Frequency constant
• $R$ = gas constant
• $T$ = Temperature
• $E_a$ = Activation energy