Chapter 16.4, Problem 16.8AFP

(a)

Interpretation Introduction

Interpretation : The concentration after $\text{10 s}$ should be calculated if the initial concentration of iodine is $\text{0}\text{.055 M}$ and the rate constant is $\text{ 7}\text{.0}\times {\text{10}}^9\text{ L/mos}\cdot \text{s}$ at $\text{23 }°\text{C}$ .

Concept Introduction :

The integrated rate law for the second-order reaction can be shown as:

  $\frac{ 1}{{\left[A\right]}_t}=k\times t+\frac{ 1}{{\left[A\right]}_0}$

Where,

  ${\left[A\right]}_0$ = Initial concentration

  $k$ = Rate constant

  $t$ = Time

  ${\left[A\right]}_t$ = Concentration after time $t$

(b)

Interpretation Introduction

Interpretation : The half-life of the reaction should be calculated if the initial concentration of iodine is $\text{0}\text{.35 M}$ and the rate constant is $\text{ 7}\text{.0 }\times {\text{ 10}}^9\text{ L/mos}\text{.s}$ at $\text{23 }°\text{C}$ .

Concept Introduction :

For second order reaction half-life $\left(t_{\text{1/2}}\right)$ is,

  $t_{\text{1/2}}=\frac{1}{k[A]}$