Chapter 16.4, Problem 6PPB

(a)

Interpretation Introduction

Interpretation:

The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions has to be calculated.

Concept Information:

pOH definition:

The $\text{pOH}$ of a solution is defined as the negative base-10 logarithm of the hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ concentration. $\text{pOH}$ scale is analogous to pH scale.

$\text{pOH}\text{=}{\text{-log[OH}}^{\text{-}}\text{]}$

On rearranging, the concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ can be calculated using pOH as follows,

${\text{[OH}}^{\text{-}}\text{]}\text{=}{\text{10}}^{\text{-pOH}}$

To Calculate: The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions at ${\text{25}}^{\circ }\text{C}$

(b)

Interpretation Introduction

Interpretation:

The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions has to be calculated.

Concept Information:

pOH definition:

The $\text{pOH}$ of a solution is defined as the negative base-10 logarithm of the hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ concentration. $\text{pOH}$ scale is analogous to pH scale.

$\text{pOH}\text{=}{\text{-log[OH}}^{\text{-}}\text{]}$

On rearranging, the concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ can be calculated using pOH as follows,

${\text{[OH}}^{\text{-}}\text{]}\text{=}{\text{10}}^{\text{-pOH}}$

To Calculate: The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions at ${\text{25}}^{\circ }\text{C}$

(c)

Interpretation Introduction

Interpretation:

The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions has to be calculated.

Concept Information:

pOH definition:

The $\text{pOH}$ of a solution is defined as the negative base-10 logarithm of the hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ concentration. $\text{pOH}$ scale is analogous to pH scale.

$\text{pOH}\text{=}{\text{-log[OH}}^{\text{-}}\text{]}$

On rearranging, the concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ can be calculated using pOH as follows,

${\text{[OH}}^{\text{-}}\text{]}\text{=}{\text{10}}^{\text{-pOH}}$

To Calculate: The concentration of hydroxide ion ${\text{[OH}}^{\text{-}}\text{]}$ of the given solutions at ${\text{25}}^{\circ }\text{C}$