From the diagrams given in the problem statement, The diagram representing a solution of a weak diprotic acid has to be identified. Which of the diagrams; represent chemically implausible situations has to be explained. Concept Information: Acid ionization constant K a : Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent. The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization. The ionization of a weak acid HA can be given as follows, HA (aq) → H + (aq) +A - (aq) The equilibrium expression for the above reaction is given below. K a = [ H + ][A - ] [ HA] Where K a is acid ionization constant, [ H + ] is concentration of hydrogen ion [ A - ] is concentration of acid anion [ HA] is concentration of the acid Diprotic and polyprotic acids: Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations. For diprotic acids, the successive ionization constants are designated as K a 1 a n d K a 2 For triprotic acids, the successive ionization constants are designated as K a 1 , K a 2 a n d K a 3
From the diagrams given in the problem statement, The diagram representing a solution of a weak diprotic acid has to be identified. Which of the diagrams; represent chemically implausible situations has to be explained. Concept Information: Acid ionization constant K a : Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent. The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization. The ionization of a weak acid HA can be given as follows, HA (aq) → H + (aq) +A - (aq) The equilibrium expression for the above reaction is given below. K a = [ H + ][A - ] [ HA] Where K a is acid ionization constant, [ H + ] is concentration of hydrogen ion [ A - ] is concentration of acid anion [ HA] is concentration of the acid Diprotic and polyprotic acids: Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations. For diprotic acids, the successive ionization constants are designated as K a 1 a n d K a 2 For triprotic acids, the successive ionization constants are designated as K a 1 , K a 2 a n d K a 3
The diagram representing a solution of a weak diprotic acid has to be identified.
Which of the diagrams; represent chemically implausible situations has to be explained.
Concept Information:
Acid ionization constant
Ka:
Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent.
The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization.
The ionization of a weak acid
HA can be given as follows,
HA(aq)→ H+(aq)+A-(aq)
The equilibrium expression for the above reaction is given below.
Ka=[H+][A-][HA]
Where
Ka is acid ionization constant,
[H+] is concentration of hydrogen ion
[A-] is concentration of acid anion
[HA] is concentration of the acid
Diprotic and polyprotic acids:
Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations.
For diprotic acids, the successive ionization constants are designated as
Ka1andKa2
For triprotic acids, the successive ionization constants are designated as
Ka1,Ka2andKa3
9. compore the Following two Venctions IN
termy Of Ronction Rate and explan in
detail the reasoning that led to your conclusion
+He p₁₂ 11-
ㅐ 15
.. +He
H #H
H
/
H
b. Compare
the Following too reactions 14
terms of reaction Rate and explain in detail
the reasoning that led to your conclusion
Н
d-C-
tłu
Na
+2446
е
-ll +2n
"H
a.
•Write all of the possible products
For the Following ronction
А
-----
H
-
H
H
+ H₂0 H+
Н
b. in Rite the complete reaction Mechaniszn
For the Formation of each product.
·C. Suggest what Reaction conditions could
Result in each product being the major
Product of the veaction:
a. Write the product For each of the
Following reactions
H
6-836-6
레
+H₂ N
A
H
A-C-C=C-C-CH + 2 Na +2 NH3 -
H H
b. Write the reaction Mechanism For.
reaction
each
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