From the diagrams given in the problem statement, The diagram representing a solution of a weak diprotic acid has to be identified. Which of the diagrams; represent chemically implausible situations has to be explained. Concept Information: Acid ionization constant K a : Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent. The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization. The ionization of a weak acid HA can be given as follows, HA (aq) → H + (aq) +A - (aq) The equilibrium expression for the above reaction is given below. K a = [ H + ][A - ] [ HA] Where K a is acid ionization constant, [ H + ] is concentration of hydrogen ion [ A - ] is concentration of acid anion [ HA] is concentration of the acid Diprotic and polyprotic acids: Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations. For diprotic acids, the successive ionization constants are designated as K a 1 a n d K a 2 For triprotic acids, the successive ionization constants are designated as K a 1 , K a 2 a n d K a 3
From the diagrams given in the problem statement, The diagram representing a solution of a weak diprotic acid has to be identified. Which of the diagrams; represent chemically implausible situations has to be explained. Concept Information: Acid ionization constant K a : Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent. The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization. The ionization of a weak acid HA can be given as follows, HA (aq) → H + (aq) +A - (aq) The equilibrium expression for the above reaction is given below. K a = [ H + ][A - ] [ HA] Where K a is acid ionization constant, [ H + ] is concentration of hydrogen ion [ A - ] is concentration of acid anion [ HA] is concentration of the acid Diprotic and polyprotic acids: Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations. For diprotic acids, the successive ionization constants are designated as K a 1 a n d K a 2 For triprotic acids, the successive ionization constants are designated as K a 1 , K a 2 a n d K a 3
The diagram representing a solution of a weak diprotic acid has to be identified.
Which of the diagrams; represent chemically implausible situations has to be explained.
Concept Information:
Acid ionization constant
Ka:
Acids ionize in water. Strong acids ionize completely whereas weak acids ionize to some limited extent.
The degree to which a weak acid ionizes depends on the concentration of the acid and the equilibrium constant for the ionization.
The ionization of a weak acid
HA can be given as follows,
HA(aq)→ H+(aq)+A-(aq)
The equilibrium expression for the above reaction is given below.
Ka=[H+][A-][HA]
Where
Ka is acid ionization constant,
[H+] is concentration of hydrogen ion
[A-] is concentration of acid anion
[HA] is concentration of the acid
Diprotic and polyprotic acids:
Acids having two or more hydrogen atoms are termed as diprotic or polyprotic acids. These acids lose one proton at a time by undergoing successive ionizations.
For diprotic acids, the successive ionization constants are designated as
Ka1andKa2
For triprotic acids, the successive ionization constants are designated as
Ka1,Ka2andKa3
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!
Q1: Answer the questions for the reaction below:
..!! Br
OH
a) Predict the product(s) of the reaction.
b) Is the substrate optically active? Are the product(s) optically active as a mix?
c) Draw the curved arrow mechanism for the reaction.
d) What happens to the SN1 reaction rate in each of these instances:
1. Change the substrate to
Br
"CI
2. Change the substrate to
3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF
4. Increase the substrate concentration by 3-fold.
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