Explanation Given information: The weight ( W ) of the door is 80 lb . The radius of gyration ( k ¯ ) is 12.5 in . The location of the mass center ( r ) from the vertical axis of rotation is 22 in . . The acceleration ( a A ) of the car is 6 ft / s 2 . Calculation: Consider the acceleration due to gravity as g = 32.2 ft / s 2 . Calculate the mass ( m ) . m = W g Substitute 80 lb for W and 32.2 ft / s 2 for g . m = 80 32.2 = 2.484 lb ⋅ s 2 / ft × 1 slugs 1 lb ⋅ s 2 / ft = 2.484 slugs Calculate the moment of inertia ( I ¯ ) . I ¯ = m k ¯ 2 Substitute 12.5 in . for k ¯ and 2.484 slugs for m . I ¯ = 2.484 slugs × ( 12.5 in . × 1 ft 12 in . ) 2 = 2.695 slugs ⋅ ft 2 Sketch the kinetic Diagram as shown in Figure (1). Refer to Figure (1), Calculate the acceleration at G with respect to A ( a G / A ) . a G / A = r a Sketch the free body diagram as shown in Figure (2). Refer to Figure (2), Consider that the angular acceleration as α = ω d ω d θ . Apply the Equations of Equilibrium. Apply the Equilibrium of moment about A is Equal to zero. ∑ M A = I G α + m a d 0 = I ¯ α + ( m r α ) r − m a A ( r cos θ ) ( I ¯ + m r 2 ) α − m r a A cos θ = 0 Substitute ω d ω d θ for α , 2

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9781259639272

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

See similar textbooks

Concept explainers

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be create…

Videos

Question

Chapter 16.2, Problem 16.133P

To determine

The smallest constant acceleration (aA) that the driver can maintain if the car’s door is to close and latch.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16.2, Problem 16.132P

Chapter 16.2, Problem 16.134P

Students have asked these similar questions

Hints: Find the closed loop transfer function and then plot the step response for diFerentvalues of K in MATLAB. Show step response plot for different values of K. Auto Controls Show solutions and provide matlab code NO COPIED ANSWERS OR WILL REPORT!!!!

37. The vertical shaft shown in Figure P12-37 is driven at a speed of 600 rpm with 4.0 hp entering through the bevel gear. Each of the two chain sprockets delivers 2.0 hp to the side to drive mixer blades in a chemical reactor vessel. The bevel gear has a diametral pitch of 5, a pitch diameter of 9.000 in, a face width of 1.31 in, and a pressure angle of 20°. Use SAE 4140 OQT 1000 steel for the shaft. See Chapter 10 for the methods for computing the forces on the bevel gear. Figure P12-37: P37-Bevel gear drive with two chain sprockets Each problem includes the following details: ■Design the complete shaft, including the specification of the overall geometry and the consideration of stress con- centration factors. The analysis would show the minimum acceptable diameter at each point on the shaft to be safe from the standpoint of strength. Homework Problems 12-24, 12-35, and 12-37 from textbook, done in spreadsheet form. Place drawings of the load, shear, and bending moment body diagrams…

35. The double-reduction, helical gear reducer shown in Figure P12-35 transmits 5.0 hp. Shaft 1 is the input, rotating at 1800 rpm and receiving power directly from an electric motor through a flexible coupling. Shaft 2 rotates at 900 rpm. Shaft 3 is the output, rotating at 300 rpm. A chain sprocket is mounted on the output shaft as shown and delivers the power upward. The data for the gears are given in Table 12-5. Each gear has a 1412° normal pressure angle and a 45° helix angle. The combinations of left- and right-hand helixes are arranged so that the axial forces oppose each other on shaft 2 as shown. Use SAE 4140 OQT 1200 for the shafts. Figure P12-35: P35-Double-reduction helical drive Each problem includes the following details: ■Design the complete shaft, including the specification of the overall geometry and the consideration of stress con- centration factors. The analysis would show the minimum acceptable diameter at each point on the shaft to be safe from the standpoint of…

Chapter 16 Solutions

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

Ch. 16.1 - Two pendulums, A and B, with the masses and...Ch. 16.1 - Two pendulums, A and B, with the masses and...Ch. 16.1 - Two solid cylinders, A and B, have the same mass m...Ch. 16.1 - Prob. 16.1FBP Ch. 16.1 - Prob. 16.2FBP Ch. 16.1 - Prob. 16.3FBP Ch. 16.1 - The 400-lb crate shown is lowered by means of two...Ch. 16.1 - A 60-lb uniform thin panel is placed in a truck...Ch. 16.1 - A 60-lb uniform thin panel is placed in a truck...Ch. 16.1 - 16.3 Knowing that the coefficient of static...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The smallest constant acceleration ( a A ) that the driver can maintain if the car’s door is to close and latch.

Concept explainers

Videos

The smallest constant acceleration (aA) that the driver can maintain if the car’s door is to close and latch.

Want to see the full answer?

Chapter 16 Solutions