Explanation Given information: The radius of brake drum is 8 in . The total mass moment of inertia ( I ¯ ) of the drum and the flywheel is 14 lb ⋅ ft ⋅ s 2 The coefficient of kinetic friction ( μ k ) between the drum and the brake shoe is 0.35. The angular velocity ( ω 0 ) of the flywheel is 360 rpm (clockwise). The magnitude of force P is 75 lb. Calculation: Show the free body diagram of brake drum as in Figure (1). Calculate the friction force ( F ) using the relation: F = μ k N Substitute 0.35 for μ k . F = 0.35 N (1) Calculate the normal force by take moment about A : ∑ M A = 0 N ( 10 in . ) + F ( 2 in . ) − ( 75 lb × 9in . ) = 0 Substitute 0.35 N for F . N ( 10 in . ) + ( 0.35 N ) ( 2 in . ) − ( 75 lb × 9in . ) = 0 10 N + 0.7 N − 675 = 0 10.7 N = 675 N = 675 10.7 N = 63.084 lb Substitute 63.084 lb for N . F = 0.35 ( 63.084 ) = 22.08 lb Show the free body and kinetic energy diagram of the flywheel as in Figure (2). Calculate the angular acceleration: Equate the moment about D for external force to effective force: ∑ M D = ∑ ( M D ) eff F r = I ¯ α Substitute 22

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9781259639272

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 16.1, Problem 16.28P

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The number of revolution (θ) executed by the flywheel before it comes to rest.

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Chapter 16.1, Problem 16.27P

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Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

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The number of revolution ( θ ) executed by the flywheel before it comes to rest.

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The number of revolution (θ) executed by the flywheel before it comes to rest.

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