As O 2 ( l ) is cooled at 1 atm, it freezes at 54.5 K to form solid I. At a lower temperature, solid I rearranges to solid II, which has a different crystal structure. Thermal measurements show that ∆H for the I → II phase transition is −743.1 J/mol, and ∆S for the same transition is −17.0 J/K mol. At what temperature are solids 1 and II in equilibrium?
As O 2 ( l ) is cooled at 1 atm, it freezes at 54.5 K to form solid I. At a lower temperature, solid I rearranges to solid II, which has a different crystal structure. Thermal measurements show that ∆H for the I → II phase transition is −743.1 J/mol, and ∆S for the same transition is −17.0 J/K mol. At what temperature are solids 1 and II in equilibrium?
Solution Summary: The author explains that the freezing of O_2(l) to form solid I is given. The temperature at which these solids, I and II are at equilibrium is
As O2(l) is cooled at 1 atm, it freezes at 54.5 K to form solid I. At a lower temperature, solid I rearranges to solid II, which has a different crystal structure. Thermal measurements show that ∆H for the I → II phase transition is −743.1 J/mol, and ∆S for the same transition is −17.0 J/K mol. At what temperature are solids 1 and II in equilibrium?
Indicate the spectroscopic transmission that requires greater energy radiation. Justification:a) NMR b) vibration c) electronica d) rotation
After an induced absorption process of an intensity, there are (without population inversion) transitions between:a) vibrational and rotational levels in the infrared region, we obtainb) vibrational levels exclusively in the infrared regionc) vibrational and rotational levels in the microwave regiond) transitions between nuclear spin levels in the radio frequency region
In a spontaneous emission process:a) the ground state population decreasesb) the excited state population decreasesc) the non-radiative component is predominantd) the emitted radiation is coherent
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