Business Driven Technology
7th Edition
ISBN: 9781259567322
Author: Paige Baltzan Instructor
Publisher: McGraw-Hill Education
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Chapter 16, Problem 7AYK
Explanation of Solution
Benefits of Free Wi-Fi in Africa:
- Better connection with the rest of the world.
- They will be able to get the current news and be aware of what is going on in other parts of the world.
- They will be able to send and receive emails.
- They will be able to send and receive photos and videos.
- They will be able to surf the web and find something that interests them.
- They will be able to learn about IT technologies and
programming . - They will be able to take online courses to improve their education and knowledge.
- They will be able to use social networks and communicate with the rest of the world.
- They will be able to use the internet to sell and purchase goods.
- They will be updated with information through the use of blogs.
10 ways wireless access might hurt remote villages in Africa include the following:
- Local business that offer internet connection for a fee might be hurt if someone provides free internet access.
- People might not have computers to connect to the free Wi-Fi.
- The free Wi-Fi connection might not be secure, so unauthorized people might gain access to sensitive information.
- People in Africa might not have the knowledge to use the internet.
- People in Africa might have bigger issues to be solved than having internet connection, such as access to clean water.
- They might access website that contain viruses.
- Computers might break or have technical issues that need to be repaired.
- Most of the people live in villages need food and water, so they might not know what to do with free internet connection while starving...
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The images I have uploaded are the part 1 to 4 and questions below are continue on the questions uploaded
5. C++ Class Template with Method Stubs
#pragma once
#include <iostream>
#include <string>
#include <stdexcept>
#include <vector>
template <typename T>
class HashTable {
private:
struct Entry {
std::string key;
T value;
bool isOccupied;
bool isDeleted;
Entry() : key(""), value(), isOccupied(false), isDeleted(false) {}
};
Entry* table;
size_t capacity;
size_t size;
double loadFactorThreshold;
size_t customHash(const std::string& key) const {
size_t hash = 5381;
for (char c : key) {
hash = ((hash << 5) + hash) + c;
}
return hash;
}
size_t probe(const std::string& key, bool forInsert = false) const;
void resize();
public:
// Constructor
HashTable(size_t initialCapacity = 101);
// Big…
this project is NOT for graded(marks) purposes, please help me with the introduction. give me answers for the project. i will include an image explaining everything about the project.
Java Graphics
(Bonus
In this lab, we'll be practicing what we learned about GUIs, and Mouse events. You will need to
implement the following:
A GUI with a drawing panel. We can click in this panel, and you will capture those clicks as a
Point (see java.awt.Point) in a PointCollection class (you need to build this).
The points need to be represented by circles.
Below the drawing panel, you will need 5 buttons:
O
о
о
○
An input button to register your mouse to the drawing panel.
A show button to paint the points in your collection on the drawing panel.
A button to shift all the points to the left by 50 pixels.
The x position of the points is not allowed to go below zero.
Another button to shift all the points to the right 50 pixels.
"
The x position of the points cannot go further than the
You can implement this GUI in any way you choose. I suggest using the BorderLayout for a panel
containing the buttons, and a GridLayout to hold the drawing panel and button panels.
Regardless of how…
Chapter 16 Solutions
Business Driven Technology
Ch. 16 - Prob. 1OCCh. 16 - Prob. 2OCCh. 16 - Prob. 1CQCh. 16 - Prob. 2CQCh. 16 - Prob. 3CQCh. 16 - Prob. 4CQCh. 16 - Prob. 5CQCh. 16 - Prob. 1RQCh. 16 - Prob. 2RQCh. 16 - Prob. 3RQ
Ch. 16 - Prob. 4RQCh. 16 - Prob. 5RQCh. 16 - Prob. 6RQCh. 16 - Prob. 7RQCh. 16 - Prob. 8RQCh. 16 - Prob. 9RQCh. 16 - Prob. 10RQCh. 16 - Prob. 4MBDCh. 16 - Prob. 5MBDCh. 16 - Prob. 6MBDCh. 16 - Prob. 7MBDCh. 16 - Prob. 8MBDCh. 16 - Prob. 1CCOCh. 16 - Prob. 2CCOCh. 16 - Prob. 3CCOCh. 16 - Prob. 4CCOCh. 16 - Prob. 5CCOCh. 16 - Prob. 1CCTCh. 16 - Prob. 2CCTCh. 16 - Prob. 3CCTCh. 16 - Prob. 4CCTCh. 16 - Prob. 5CCTCh. 16 - Prob. 6CCTCh. 16 - Prob. 1AYKCh. 16 - Prob. 2AYKCh. 16 - Prob. 4AYKCh. 16 - Prob. 5AYKCh. 16 - Prob. 6AYKCh. 16 - Prob. 7AYKCh. 16 - Prob. 8AYK
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