Business Driven Technology
7th Edition
ISBN: 9781259567322
Author: Paige Baltzan Instructor
Publisher: McGraw-Hill Education
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Question
Chapter 16, Problem 1CCT
Program Plan Intro
E-business:
The information and communication technology is used for business support activities is called e-business.
- In e-business, the internet is used to buy, sell, provide customer service and collaborate with business partners.
- The e-business competes in the global market by providing the best customer service, providing materials economically and develops the products faster and efficiently.
Disruptive technology:
This technology reanalyzes the competitive playing fields of their corresponding markets. Its motive is to destroy old markets and open new ones.
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1. [20 pts] What is the output of the program? Please explain why.
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Please run and debug the following program and answer the questions.
(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter 16 Solutions
Business Driven Technology
Ch. 16 - Prob. 1OCCh. 16 - Prob. 2OCCh. 16 - Prob. 1CQCh. 16 - Prob. 2CQCh. 16 - Prob. 3CQCh. 16 - Prob. 4CQCh. 16 - Prob. 5CQCh. 16 - Prob. 1RQCh. 16 - Prob. 2RQCh. 16 - Prob. 3RQ
Ch. 16 - Prob. 4RQCh. 16 - Prob. 5RQCh. 16 - Prob. 6RQCh. 16 - Prob. 7RQCh. 16 - Prob. 8RQCh. 16 - Prob. 9RQCh. 16 - Prob. 10RQCh. 16 - Prob. 4MBDCh. 16 - Prob. 5MBDCh. 16 - Prob. 6MBDCh. 16 - Prob. 7MBDCh. 16 - Prob. 8MBDCh. 16 - Prob. 1CCOCh. 16 - Prob. 2CCOCh. 16 - Prob. 3CCOCh. 16 - Prob. 4CCOCh. 16 - Prob. 5CCOCh. 16 - Prob. 1CCTCh. 16 - Prob. 2CCTCh. 16 - Prob. 3CCTCh. 16 - Prob. 4CCTCh. 16 - Prob. 5CCTCh. 16 - Prob. 6CCTCh. 16 - Prob. 1AYKCh. 16 - Prob. 2AYKCh. 16 - Prob. 4AYKCh. 16 - Prob. 5AYKCh. 16 - Prob. 6AYKCh. 16 - Prob. 7AYKCh. 16 - Prob. 8AYK
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