Basic Chemistry (5th Edition)
Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
Question
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Chapter 16, Problem 33CI
Interpretation Introduction

(a)

Interpretation:

  MnO4-(aq) + C2O42-Mn2+(aq) + CO2(g)

To write the balanced oxidation half-reaction

Concept Introduction:

Here are the steps to balance redox reaction in an acidic medium:

  1. Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.
  2. To balance every half reaction in acidic medium, use H2O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Interpretation Introduction

(b)

Interpretation:

  MnO4-(aq) + C2O42-Mn2+(aq) + CO2(g)

To write the balanced reduction half-reaction

Concept Introduction:

Here are the steps to balance redox reaction sin an acidic medium:

  1. Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.
  2. To balance every half reaction in acidic medium, use H2O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Interpretation Introduction

(c)

Interpretation:

MnO4-(aq) + C2O42-Mn2+(aq) + CO2(g)

To write the balanced ionic equation for the reaction

Concept Introduction:

Here are the steps to balance redox reaction sin an acidic medium:

  1. Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.
  2. To balance every half reaction in acidic medium, use H2O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Interpretation Introduction

(d)

Interpretation:

If 24.6 ml of a KMnO4 solution is needed to titrate a solution containing 0.758 g of Na2C2O4, the molarity of the KMnO4 solution should be determined.

Concept Introduction:

Moles = massmolar mass  

  Molarity = moles of soluteLiter of solution

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Chapter 16 Solutions

Basic Chemistry (5th Edition)

Ch. 16.1 - Prob. 16.11QAPCh. 16.1 - Prob. 16.12QAPCh. 16.2 - Prob. 16.13QAPCh. 16.2 - Prob. 16.14QAPCh. 16.2 - Prob. 16.15QAPCh. 16.2 - Prob. 16.16QAPCh. 16.2 - Prob. 16.17QAPCh. 16.2 - Prob. 16.18QAPCh. 16.2 - Prob. 16.19QAPCh. 16.2 - Prob. 16.20QAPCh. 16.2 - Prob. 16.21QAPCh. 16.2 - Prob. 16.22QAPCh. 16.3 - Prob. 16.23QAPCh. 16.3 - Prob. 16.24QAPCh. 16.3 - Prob. 16.25QAPCh. 16.3 - Prob. 16.26QAPCh. 16.3 - Prob. 16.27QAPCh. 16.3 - Prob. 16.28QAPCh. 16.4 - Prob. 16.29QAPCh. 16.4 - Prob. 16.30QAPCh. 16.4 - Prob. 16.31QAPCh. 16.4 - Prob. 16.32QAPCh. 16.4 - Prob. 16.33QAPCh. 16.4 - Prob. 16.34QAPCh. 16.5 - Prob. 16.35QAPCh. 16.5 - Prob. 16.36QAPCh. 16.5 - Prob. 16.37QAPCh. 16.5 - Prob. 16.38QAPCh. 16.6 - Prob. 16.39QAPCh. 16.6 - Prob. 16.40QAPCh. 16.6 - Prob. 16.41QAPCh. 16.6 - Prob. 16.42QAPCh. 16.6 - Prob. 16.43QAPCh. 16.6 - Prob. 16.44QAPCh. 16 - Prob. 16.45FUCh. 16 - Prob. 16.46FUCh. 16 - Prob. 16.47FUCh. 16 - Prob. 16.48FUCh. 16 - Prob. 16.49UTCCh. 16 - Prob. 16.50UTCCh. 16 - Prob. 16.51UTCCh. 16 - Prob. 16.52UTCCh. 16 - Prob. 16.53UTCCh. 16 - Prob. 16.54UTCCh. 16 - Prob. 16.55AQAPCh. 16 - Prob. 16.56AQAPCh. 16 - Prob. 16.57AQAPCh. 16 - Prob. 16.58AQAPCh. 16 - Prob. 16.59AQAPCh. 16 - Prob. 16.60AQAPCh. 16 - Prob. 16.61AQAPCh. 16 - Prob. 16.62AQAPCh. 16 - Prob. 16.63AQAPCh. 16 - Prob. 16.64AQAPCh. 16 - Prob. 16.65AQAPCh. 16 - Prob. 16.66AQAPCh. 16 - Prob. 16.67AQAPCh. 16 - Prob. 16.68AQAPCh. 16 - Prob. 16.69AQAPCh. 16 - Prob. 16.70AQAPCh. 16 - Prob. 16.71AQAPCh. 16 - Prob. 16.72AQAPCh. 16 - Prob. 16.73AQAPCh. 16 - Prob. 16.74AQAPCh. 16 - Prob. 16.75AQAPCh. 16 - Prob. 16.76AQAPCh. 16 - Prob. 16.77CQCh. 16 - Prob. 16.78CQCh. 16 - Prob. 16.79CQCh. 16 - Prob. 16.80CQCh. 16 - Prob. 16.81CQCh. 16 - Prob. 16.82CQCh. 16 - Prob. 16.83CQCh. 16 - Prob. 16.84CQCh. 16 - Prob. 16.85CQCh. 16 - Prob. 16.86CQCh. 16 - Prob. 16.87CQCh. 16 - Prob. 16.88CQCh. 16 - Prob. 33CICh. 16 - Prob. 34CICh. 16 - Prob. 35CICh. 16 - Prob. 36CICh. 16 - Prob. 37CICh. 16 - Prob. 38CICh. 16 - Prob. 39CICh. 16 - Prob. 40CI
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