
Concept explainers
Interpretation:
The pH for the titration of

Explanation of Solution
Given,
Titration of
Addition of
Given system is titration of
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
Limiting reagent:
According to the balanced chemical equation, for 1 mole of
But there is excess amount of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 0.50 ml = 1.50 ml (or)
One mole of
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
Limiting reagent:
According to the balanced chemical equation, for 1 mole of
But there is excess amount of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 1 ml = 2 ml (or)
One mole of
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | 0 | Excess |
The total volume of the given solution is 1 ml + 2.4 ml = 3.4 ml (or)
The resulting solution is neutral. Therefore,
Hence,
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
Limiting reagent:
According to the balanced chemical equation, for 1 mole of
But there is less amount of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 3 ml = 4 ml (or)
The concentration of
The titration curve is shown below,
Figure 1
The curve in Question 16.21 has the same general form, but the equivalence point occurs at half the volume the equivalence point occurs in Question 16.23.
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Chapter 16 Solutions
Chemistry Principles And Practice
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