
Concept explainers
Interpretation:
The pH of the titration of

Explanation of Solution
Given,
Titration of
Addition of
Given system is titration of
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 0.25 ml = 1.25 ml (or) 0.0625 L
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 0.50 ml = 1.50 ml (or) 0.0015 L
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | 0 | Excess |
The total volume of the given solution is 1 ml + 1.2 ml = 2.20 ml (or) 0.0022 L
The resulting solution is neutral. Therefore,
Hence,
The concentration of
Addition of
Given system is titration of
The given titration is shown below,
Moles of
Moles of
ICE table:
S (mol) | 0 | Excess | ||
R (mol) | ||||
F(mol) | 0 | Excess |
The total volume of the given solution is 1 ml + 1.5 ml = 2.5 ml (or) 0.0025 L
The concentration of
The titration curve is given below,
Figure 1
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Chapter 16 Solutions
Chemistry Principles And Practice
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