Chapter 16, Problem 16.15QE

Interpretation Introduction

Interpretation:

Numbers of millimoles of KOH that are needed to neutralize $\text{35}\text{.1 mL of 0}\text{.101 M}$ nitric acid has to be calculated.

Concept introduction:

The mole of the solution can be calculated by using following formula

  $\begin{array}{l}\text{Molarity of the solution}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{litre}}\\ \text{Number}\text{of}\text{moles}\text{=}\text{Molarity of the solution}\text{×}\text{Volume}\text{of}\text{solution}\text{in}\text{litre}\end{array}$