(a)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids
- Amorphous solid
(a)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well defined ordered arrangement of particles whereas amorphous solids have disordered at an atomic level because particles are held together in a completely random formation.
Noble gases have completely filled valence shell configuration therefore they have weak dispersion forces between atoms and only exist in gaseous state.
(b)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids
- Amorphous solid
(b)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well defined ordered arrangement of particles whereas amorphous solids have disordered at an atomic level because particles are held together in a completely random formation.
Molecular solids are a type of crystalline solid which are composed of molecules which have weak intermolecular forces. In these solids, the constituent particle must be some molecule.
(c)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids
- Amorphous solid
(c)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well defined ordered arrangement of particles whereas amorphous solids have disordered arrangement at an atomic level because particles are held together in a completely random formation.
Metallic solids are composed of metal atoms which are bonded with metallic bonds. Metallic bonds are the electrostatic force of attraction between positive charge metal ions and free mobile electrons.
(d)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids
- Amorphous solid
(d)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well-defined ordered arrangement of particles, whereas amorphous solids have disordered arrangement at an atomic level because particles are held together in a completely random formation.
Network solids are types of crystalline solid which are mainly composed of atoms which are bonded through covalent bonds to form a large cross network. In these solids, the constituent particle must be some atoms which are bonded with strong covalent bonds.
(e)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids
- Amorphous solid
(e)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well defined ordered arrangement of particles whereas amorphous solids have disordered at an atomic level because particles are held together in a completely random formation.
Molecular solids are a type of crystalline solid which are composed of molecules which have weak intermolecular forces. In these solids, the constituent particle must be some molecule.
(f)
Interpretation: The type of solid for given substance needs to be determined.
Concept Introduction:
Solid state has strong intermolecular force of attraction between particles whereas the gaseous particles have weakest intermolecular forces between particles. Due to intermolecular force of attraction between particles, different interconversions are possible between these three states like evaporation, condensation, sublimation, etc.
On the basis of structure and intermolecular interactions, solids can further classified as:
- Crystalline solids - Molecular solids, network solid, ionic solids, metallic solids.
- Amorphous solid.
(f)

Answer to Problem 141AE
Explanation of Solution
Crystalline solids have well-defined ordered arrangement of particles whereas amorphous solids have disordered arrangement at an atomic level because particles are held together in a completely random formation.
Metallic solids are composed of metal atoms which are bonded with metallic bonds. Metallic bonds are the electrostatic force of attraction between positive charge metal ions and free mobile electrons.
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Chapter 16 Solutions
EBK WEBASSIGN FOR ZUMDAHL'S CHEMICAL PR
- Consider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forwardV Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forward
- Consider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forwardWhat kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forwardFor the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forward
- Problem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forwardFeedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forwardCan I please get the blank spaces answered/answers?arrow_forward
- 1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forward
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