Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined. Concept introduction: Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

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Answer 1

Question

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

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Answer 2

Question

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

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Answer 3

Question

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

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Answer 4

Question

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

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Answer 5

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

Answer 6

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

Answer 7

Chapter 16, Problem 10P

Interpretation Introduction

Interpretation:

Mammals cannot synthesize carbohydrate from acetyl-CoA but the carbons of acetyl-CoA can be incorporated to glucose and amino acids via metabolic pathways and pathway should be determined.

Concept introduction:

Mammals cannot synthesize glucose directly from acetyl-CoA but the carbons of acetyl-CoA enter the TCA or tricarboxylic acid cycle and forms oxaloacetate. The oxaloacetate then gets converted to glucose by gluconeogenesis.

Answer 8

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Answer 9

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Answer 10

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Answer 11

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