Given that 1-phenyl-2-butene has an ultraviolet absorption at λ max = 208nm (∈ = 8000). On treatment with a small amount of strong acid it isomerizes to give a new compound with λ max = 250nm (∈ = 15,800). A structure for the isomer is to be proposed and a mechanism for its formation has to be suggested. Concept introduction: Among two isomers with same molecular formula, the isomer that has extended conjugation will have a higher λ max value than the other. To propose: A structure for the isomer which has an ultraviolet absorption at λ max = 250 nm (∈ = 15,800) obtained when 1-phenyl-2-butene with λ max = 208 nm (∈ = 8000) is treated with strong acids. Further to propose a mechanism for its formation.
Given that 1-phenyl-2-butene has an ultraviolet absorption at λ max = 208nm (∈ = 8000). On treatment with a small amount of strong acid it isomerizes to give a new compound with λ max = 250nm (∈ = 15,800). A structure for the isomer is to be proposed and a mechanism for its formation has to be suggested. Concept introduction: Among two isomers with same molecular formula, the isomer that has extended conjugation will have a higher λ max value than the other. To propose: A structure for the isomer which has an ultraviolet absorption at λ max = 250 nm (∈ = 15,800) obtained when 1-phenyl-2-butene with λ max = 208 nm (∈ = 8000) is treated with strong acids. Further to propose a mechanism for its formation.
Given that 1-phenyl-2-butene has an ultraviolet absorption at λmax = 208nm (∈ = 8000). On treatment with a small amount of strong acid it isomerizes to give a new compound with λmax = 250nm (∈ = 15,800). A structure for the isomer is to be proposed and a mechanism for its formation has to be suggested.
Concept introduction:
Among two isomers with same molecular formula, the isomer that has extended conjugation will have a higher λmax value than the other.
To propose:
A structure for the isomer which has an ultraviolet absorption at λmax = 250 nm (∈ = 15,800) obtained when 1-phenyl-2-butene with λmax = 208 nm (∈ = 8000) is treated with strong acids. Further to propose a mechanism for its formation.
at 32.0 °C?
What is the osmotic pressure (in atm) of a 1.46 M aqueous solution of urea [(NH2), CO] at 3
Round your answer to 3 significant digits.
Reagan is doing an atomic absorption experiment that requires a set of zinc standards in the 0.4-1.6 ppm range. A 1000 ppm Zn solution was prepared by dissolving the necessary amount of solid Zn(NO3)2 in water. The standards can be prepared by diluting the 1000 ppm Zn solution. Table 1 shows one possible set of serial dilutions (stepwise dilution of a solution) that Reagan could perform to make the necessary standards. Solution A was prepared by diluting 5.00 ml of the 1000 ppm Zn standard to 50.00 ml. Solutions C-E are called "calibration standards" because they will be used to calibrate the atomic absorption spectrometer.
a. Compare the solution concentrations expressed as ppm Zn and ppm Zn(NO3)2. Compare the concentrations expressed as M Zn and M Zn(NO3)2
- Which units allow easy conversion between chemical species (e.g. Zn and Zn(NO3)2)?
- Which units express concentrations in numbers with easily expressed magnitudes?
- Suppose you have an analyte for which you don't know the molar…