EP ORGANIC CHEMISTRY,24 MONTH-OWLV2
EP ORGANIC CHEMISTRY,24 MONTH-OWLV2
9th Edition
ISBN: 9781305084391
Author: McMurry
Publisher: CENGAGE L
Question
Book Icon
Chapter 15.SE, Problem 42AP
Interpretation Introduction

Interpretation:

4-Pyrone on treatment with acid gets protonated on the carbonyl group oxygen to yield a stable product. Why the structure is so stable is to be explained using resonance structures and the Huckel’s (4n+2) rule.

Concept introduction:

A compound to become aromatic should obey Huckel’s rule. According to Huckel’s rule, any specie that is cyclic, planar and has (4n+2) delocalized Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable.

To explain:

Using resonance structures and the Huckel’s (4n+2) rule why the protonated product obtained when 4-pyrone reacts with acid is so stable.

Blurred answer
Students have asked these similar questions
6. Show how you would accomplish the following transformations. (Show the steps and reagents/solvents needed) 2-methylpropene →2,2-dimethyloxiran I
4) Answer the following exercise with curved arrows indicating who is a nucleophile or Who is the electrophile? 2.44 Predict the structure of the product formed in the reaction of the organic base pyridine with the organic acid acetic acid, and use curved arrows to indicate the direction of electron flow. 7 H3C OH N Pyridine Acetic acid
Using the data provided please help me answer this question.  Determine the concentration of the iron(Ill) salicylate in the unknown directly from to graph and from the best fit trend-line (least squares analysis) of the graph that yielded a straight line.

Chapter 15 Solutions

EP ORGANIC CHEMISTRY,24 MONTH-OWLV2

Ch. 15.6 - Prob. 11PCh. 15.6 - How many electrons does each of the four nitrogen...Ch. 15.SE - Give IUPAC names for the following substances (red...Ch. 15.SE - All-cis cyclodecapentaene is a stable molecule...Ch. 15.SE - 1, 6-Methanonaphthalene has an interesting 1H NMR...Ch. 15.SE - Prob. 16VCCh. 15.SE - Azulene, an isomer of naphthalene, has a...Ch. 15.SE - Give IUPAC names for the following compounds:Ch. 15.SE - Draw structures corresponding to the following...Ch. 15.SE - Prob. 20APCh. 15.SE - Prob. 21APCh. 15.SE - Draw and name all possible aromatic compounds with...Ch. 15.SE - Propose structures for aromatic hydrocarbons that...Ch. 15.SE - Look at the three resonance structures of...Ch. 15.SE - Prob. 25APCh. 15.SE - Prob. 26APCh. 15.SE - Look at the five resonance structures for...Ch. 15.SE - Prob. 28APCh. 15.SE - 3-Chlorocyclopropene, on treatment with AgBF4,...Ch. 15.SE - Prob. 30APCh. 15.SE - Prob. 31APCh. 15.SE - Prob. 32APCh. 15.SE - Which would you expect to be most stable,...Ch. 15.SE - How might you convert 1, 3, 5, 7-cyclononatetraene...Ch. 15.SE - Calicene, like azulene (Problem 15-17), has an...Ch. 15.SE - Pentalene is a most elusive molecule that has been...Ch. 15.SE - Prob. 37APCh. 15.SE - Prob. 38APCh. 15.SE - Compound A, C8H10, yields three substitution...Ch. 15.SE - Prob. 40APCh. 15.SE - Propose structures for compounds that fit the...Ch. 15.SE - Prob. 42APCh. 15.SE - Prob. 43APCh. 15.SE - N-Phenylsydnone, so-named because it was first...Ch. 15.SE - Prob. 45APCh. 15.SE - Prob. 46APCh. 15.SE - Prob. 47APCh. 15.SE - Propose a structure for a molecule C14H12 that has...Ch. 15.SE - The proton NMR spectrum for a compound with...Ch. 15.SE - The proton NMR spectrum of a compound with formula...Ch. 15.SE - Aromatic substitution reactions occur by addition...Ch. 15.SE - Prob. 52APCh. 15.SE - Consider the aromatic anions below and their...Ch. 15.SE - After the reaction below, the chemical shift of Ha...Ch. 15.SE - Prob. 55APCh. 15.SE - Azo dyes are the major source of artificial color...
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning