Basic Chemistry
Basic Chemistry
6th Edition
ISBN: 9780134878119
Author: Timberlake, Karen C. , William
Publisher: Pearson,
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Chapter 15.1, Problem 6PP

(a)

Interpretation Introduction

Interpretation: Assign oxidation number to Al

Concept Introduction: The rules for assigning oxidation number to elements are:

  • For an element in its free state it is assigned an oxidation number of zero.
  • Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
  • Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
  • In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
  • For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.

If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.

(b)

Interpretation Introduction

Interpretation: Assign oxidation number to Al3+

Concept Introduction: The rules for assigning oxidation number to elements are:

  • For an element in its free state it is assigned an oxidation number of zero.
  • Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
  • Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
  • In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
  • For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.

If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.

(c)

Interpretation Introduction

Interpretation: Assign oxidation number to F-

Concept Introduction: The rules for assigning oxidation number to elements are:

  • For an element in its free state it is assigned an oxidation number of zero.
  • Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
  • Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
  • In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
  • For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.

If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.

(d)

Interpretation Introduction

Interpretation: Assign oxidation number to N2

Concept Introduction: The rules for assigning oxidation number to elements are:

  • For an element in its free state it is assigned an oxidation number of zero.
  • Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
  • Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
  • In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
  • For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.

If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.

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2.0

Chapter 15 Solutions

Basic Chemistry

Ch. 15.1 - Prob. 11PPCh. 15.1 - Prob. 12PPCh. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - Prob. 15PPCh. 15.1 - Prob. 16PPCh. 15.1 - Prob. 17PPCh. 15.1 - Prob. 18PPCh. 15.1 - Prob. 19PPCh. 15.1 - Prob. 20PPCh. 15.2 - Balance each of the following half-reactions in...Ch. 15.2 - Prob. 22PPCh. 15.2 - Prob. 23PPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Prob. 29PPCh. 15.3 - Prob. 30PPCh. 15.3 - Prob. 31PPCh. 15.3 - Prob. 32PPCh. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - Prob. 36PPCh. 15.4 - What we call "tin cans" are really iron cans...Ch. 15.4 - Prob. 38PPCh. 15.4 - Prob. 39PPCh. 15.4 - Prob. 40PPCh. 15.4 - Prob. 41PPCh. 15.4 - Prob. 42PPCh. 15 - Prob. 43UTCCh. 15 - Prob. 44UTCCh. 15 - Prob. 45UTCCh. 15 - Prob. 46UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Prob. 50UTCCh. 15 - Prob. 51UTCCh. 15 - Prob. 52UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - In the mitochondria of human cells, energy is...Ch. 15 - Prob. 58APPCh. 15 - Prob. 59APPCh. 15 - Prob. 60APPCh. 15 - Prob. 61APPCh. 15 - Prob. 62APPCh. 15 - Prob. 63APPCh. 15 - Write the balanced half-reactions and a balanced...Ch. 15 - Prob. 65APPCh. 15 - Use the activity series in Table 15.3 to predict...Ch. 15 - Prob. 67APPCh. 15 - Prob. 68APPCh. 15 - Prob. 69APPCh. 15 - Prob. 70APPCh. 15 - Prob. 71APPCh. 15 - In an acidic dry-cell battery, the following...Ch. 15 - Steel bolts made for sailboats are coated with...Ch. 15 - Copper cooking pans are stainless steel pans...Ch. 15 - Prob. 75CPCh. 15 - Prob. 76CPCh. 15 - Prob. 77CPCh. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - Prob. 81CPCh. 15 - Prob. 82CPCh. 15 - Prob. 83CPCh. 15 - Prob. 84CPCh. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CP
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