EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119227946
Author: Willard
Publisher: VST
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Chapter 15, Problem 9RQ
Interpretation Introduction
Interpretation:
Out of the four classes of substances amongst acids, bases, salt and alcohols the one that is electrolytes have to be identified.
Concept Introduction:
An electrolyte refers to an ionic compound that on solvation in polar protic solvents ionizes to yield cationic and anionic species. The free movement of such ionic species results in the conduction of electricity.
Three subcategories exist for electrolyte namely strong electrolyte weak electrolyte and non-electrolyte. The strong electrolytes on dissolution exhibit
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The average blood pH is 7.40. The blood volume in humans, on average, is 5 liters. On average bicarbonate concentration in blood is 25 mM. A vinegar jar has a label that says its acetic acid concentration is 3.0%, meaning 3.0 g of acetic acid in 100 mL vinegar. (1) How many mL of vinegar does a person have to intake in order to lower the blood pH to 7.25? (2) if ALL the bicarbonate in 5.0 L of blood is neutralized by vinegar, how many mL of vinegar will be needed? (3) When all the bicarbonate ions are neutralized to carbonic acid, what will be the resulting blood pH?
Note: pKa values for carbonic acid (diprotic acid) are 6.4 and 10.3, respectively.
What volume (in mL) of the following acid would be required for complete neutralization of 50.00mL of 0.100 M NaOH?
a. 0.100 M HCl(aq)
>
Sodium hydrogen carbonate (NaHCO3), also known as sodium bicarbonate or "baking soda", can be used to relieve acid
indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid
(HCI), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3 neutralizes
excess HCl through this reaction:
HCl(aq) + NaHCO3(aq) → NaCl(aq) + H₂O(1) + CO₂(g)
-
A
The CO₂ gas produced is what makes you burp after drinking the solution.
ol
Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 200. mL of a 0.067 M HCl
solution. What mass of NaHCO3 would he need to ingest to neutralize this much HCl ? Round your answer to 2 significant
digits.
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5.0
x10
X
?
5
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Chapter 15 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 15.1 - Prob. 15.1PCh. 15.1 - Prob. 15.2PCh. 15.2 - Prob. 15.3PCh. 15.2 - Prob. 15.4PCh. 15.3 - Prob. 15.5PCh. 15.4 - Prob. 15.6PCh. 15.5 - Prob. 15.7PCh. 15.6 - Prob. 15.8PCh. 15 - Prob. 1RQCh. 15 - Prob. 2RQ
Ch. 15 - Prob. 3RQCh. 15 - Prob. 4RQCh. 15 - Prob. 5RQCh. 15 - Prob. 6RQCh. 15 - Prob. 7RQCh. 15 - Prob. 8RQCh. 15 - Prob. 9RQCh. 15 - Prob. 10RQCh. 15 - Prob. 11RQCh. 15 - Prob. 12RQCh. 15 - Prob. 13RQCh. 15 - Prob. 14RQCh. 15 - Prob. 15RQCh. 15 - Prob. 16RQCh. 15 - Prob. 17RQCh. 15 - Prob. 18RQCh. 15 - Prob. 19RQCh. 15 - Prob. 20RQCh. 15 - Prob. 21RQCh. 15 - Prob. 22RQCh. 15 - Prob. 23RQCh. 15 - Prob. 24RQCh. 15 - Prob. 25RQCh. 15 - Prob. 26RQCh. 15 - Prob. 27RQCh. 15 - Prob. 28RQCh. 15 - Prob. 1PECh. 15 - Prob. 2PECh. 15 - Prob. 3PECh. 15 - Prob. 4PECh. 15 - Prob. 5PECh. 15 - Prob. 6PECh. 15 - Prob. 7PECh. 15 - Prob. 8PECh. 15 - Prob. 9PECh. 15 - Prob. 10PECh. 15 - Prob. 11PECh. 15 - Prob. 12PECh. 15 - Prob. 13PECh. 15 - Prob. 14PECh. 15 - Prob. 15PECh. 15 - Prob. 16PECh. 15 - Prob. 17PECh. 15 - Prob. 18PECh. 15 - Prob. 19PECh. 15 - Prob. 20PECh. 15 - Prob. 21PECh. 15 - Prob. 22PECh. 15 - Prob. 23PECh. 15 - Prob. 24PECh. 15 - Prob. 25PECh. 15 - Prob. 26PECh. 15 - Prob. 27PECh. 15 - Prob. 28PECh. 15 - Prob. 29PECh. 15 - Prob. 30PECh. 15 - Prob. 31PECh. 15 - Prob. 32PECh. 15 - Prob. 33PECh. 15 - Prob. 34PECh. 15 - Prob. 35PECh. 15 - Prob. 36PECh. 15 - Prob. 37PECh. 15 - Prob. 38PECh. 15 - Prob. 39PECh. 15 - Prob. 40PECh. 15 - Prob. 41PECh. 15 - Prob. 42PECh. 15 - Prob. 43PECh. 15 - Prob. 44PECh. 15 - Prob. 45AECh. 15 - Prob. 46AECh. 15 - Prob. 47AECh. 15 - Prob. 48AECh. 15 - Prob. 49AECh. 15 - Prob. 50AECh. 15 - Prob. 51AECh. 15 - Prob. 52AECh. 15 - Prob. 53AECh. 15 - Prob. 54AECh. 15 - Prob. 55AECh. 15 - Prob. 56AECh. 15 - Prob. 57AECh. 15 - Prob. 58AECh. 15 - Prob. 59AECh. 15 - Prob. 60AECh. 15 - Prob. 61AECh. 15 - Prob. 62AECh. 15 - Prob. 63AECh. 15 - Prob. 64AECh. 15 - Prob. 65AECh. 15 - Prob. 66AECh. 15 - Prob. 67AECh. 15 - Prob. 68AECh. 15 - Prob. 69AECh. 15 - Prob. 70AECh. 15 - Prob. 71AECh. 15 - Prob. 72AECh. 15 - Prob. 73CECh. 15 - Prob. 74CE
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- Reactions represented by the following equations take place in water solutions. Write each molecular equation in total ionic form, then identify spectator ions and write the equations in net ionic form. Solids that do not dissolve are designated by s, gases that do not dissolve are designated by g, and substances that dissolve but do not dissociate appear in blue. a. H2O(l)+Na2SO3(aq)+SO2(aq)2NaHSO3(aq) b. 3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+2NO(g)+4H2O(l) c. 2HCl(aq)+CaO(s)CaCl2(aq)+H2O(l) d. CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(aq)+H2O(l) e. MnO2(s)+4HCl(aq)MnCl2(aq)+Cl2(aq)+2H2O(l) f. 2AgNO3(aq)+Cu(s)Cu(NO3)2(aq)+2Ag(s)arrow_forwardOne half liter (500. mL) of 2.50 M HCl is mixed with 250. mL of 3.75 M HCl. Assuming the total solution volume after mixing is 750. mL, what is the concentration of hydrochloric acid in the resulting solution? What is its pH?arrow_forwardA solution of sodium cyanide, NaCN, has a pH of 12.10. How many grams of NaCN are in 425 mL of a solution with the same pH?arrow_forward
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