Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 5, Problem 5.31E

Reactions represented by the following equations take place in water solutions. Write each molecular equation in total ionic form, then identify spectator ions and write the equations in net ionic form. Solids that do not dissolve are designated by (s), gases that do not dissolve are designated by (g), and substances that dissolve but do not dissociate appear in blue.

a. H 2 O ( l ) + Na 2 SO 3 ( aq ) + SO 2 ( aq ) 2NaHSO 3 ( aq )

b. 3Cu ( s ) + 8HNO 3 ( aq )                                                 3 Cu ( NO 3 ) 2 ( aq ) + 2 NO ( g ) + 4H 2 O ( l )

c. 2HCl ( aq ) + CaO ( s ) CaCl 2 ( aq ) + H 2 O ( l )

d. CaCO 3 ( s ) + 2 HCl ( aq ) CaCl 2 ( aq ) + CO 2 ( aq ) + H 2 O ( l )

e. MnO 2 ( s ) + 4 HCl ( aq ) MnCl 2 ( aq ) + Cl 2 ( aq ) + 2 H 2 O ( l )

f. 2AgNO 3 ( aq ) + Cu ( s ) Cu ( NO 3 ) 2 ( aq ) + 2Ag ( s )

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

The given equation is to be written in total ionic form. The spectator ionsare to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is H2O(l)+2Na+(aq)+SO32(aq)+SO2(aq)2Na+(aq)+2H+(aq)+2SO32(aq). The spectator ions are Na+ and SO32. The net ionic equation is H2O(l)+SO2(aq)2H+(aq)+SO32(aq).

Explanation of Solution

The given reaction is shown below.

H2O(l)+Na2SO3(aq)+SO2(aq)2NaHSO3(aq)

The total ionic form of given reaction can be written as shown below.

H2O(l)+2Na+(aq)+SO32(aq)+SO2(aq)2Na+(aq)+2H+(aq)+2SO32(aq)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ions are Na+ and SO32.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

H2O(l)+SO2(aq)2H+(aq)+SO32(aq)

Conclusion

The total ionic form of given reaction is

H2O(l)+2Na+(aq)+SO32(aq)+SO2(aq)2Na+(aq)+2H+(aq)+2SO32(aq).

The spectator ions are Na+ and SO32.

The net ionic equation is H2O(l)+SO2(aq)2H+(aq)+SO32(aq).

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

The given equation is to be written in total ionic form. The spectator ions are to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is 3Cu(s)+8H+(aq)+8NO3(aq)3Cu2+(aq)+6NO3(aq)+2NO(g)+4H2O(l). The spectator ion is 6NO3. The net ionic equation is 3Cu(s)+8H+(aq)+2NO3(aq)3Cu2+(aq)+2NO(g)+4H2O(l).

Explanation of Solution

The given reaction is shown below.

3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+2NO(g)+4H2O(l)

The total ionic form of given reaction can be written as shown below.

3Cu(s)+8H+(aq)+8NO3(aq)3Cu2+(aq)+6NO3(aq)+2NO(g)+4H2O(l)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ion is 6NO3.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

3Cu(s)+8H+(aq)+2NO3(aq)3Cu2+(aq)+2NO(g)+4H2O(l)

Conclusion

The total ionic form of given reaction is 3Cu(s)+8H+(aq)+8NO3(aq)3Cu2+(aq)+6NO3(aq)+2NO(g)+4H2O(l). The spectator ion is 6NO3. The net ionic equation is 3Cu(s)+8H+(aq)+2NO3(aq)3Cu2+(aq)+2NO(g)+4H2O(l).

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

The given equation is to be written in total ionic form. The spectator ions are to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is

2H+(aq)+2Cl(aq)+CaO(s)Ca2+(aq)+2Cl(aq)+H2O(l).

The spectator ion is Cl. The net ionic equation is

2H+(aq)+CaO(s)Ca2+(aq)+H2O(l).

Explanation of Solution

The given reaction is shown below.

2HCl(aq)+CaO(s)CaCl2(aq)+H2O(l)

The total ionic form of given reaction can be written as shown below.

2H+(aq)+2Cl(aq)+CaO(s)Ca2+(aq)+2Cl(aq)+H2O(l)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ion is Cl.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

2H+(aq)+CaO(s)Ca2+(aq)+H2O(l)

Conclusion

The total ionic form of given reaction is 2H+(aq)+2Cl(aq)+CaO(s)Ca2+(aq)+2Cl(aq)+H2O(l). The spectator ion is Cl. The net ionic equation is 2H+(aq)+CaO(s)Ca2+(aq)+H2O(l).

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

The given equation is to be written in total ionic form. The spectator ions are to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is CaCO3(s)+2H+(aq)+2Cl(aq)Ca2+(aq)+2Cl(aq)+CO2(aq)+H2O(l). The spectator ion is Cl. The net ionic equation is CaCO3(s)+2H+(aq)Ca2+(aq)+CO2(aq)+H2O(l).

Explanation of Solution

The given reaction is shown below.

CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(aq)+H2O(l)

The total ionic form of given reaction can be written as shown below.

CaCO3(s)+2H+(aq)+2Cl(aq)Ca2+(aq)+2Cl(aq)+CO2(aq)+H2O(l)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ion is Cl.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

CaCO3(s)+2H+(aq)Ca2+(aq)+CO2(aq)+H2O(l)

Conclusion

The total ionic form of given reaction is CaCO3(s)+2H+(aq)+2Cl(aq)Ca2+(aq)+2Cl(aq)+CO2(aq)+H2O(l). The spectator ion is Cl. The net ionic equation is CaCO3(s)+2H+(aq)Ca2+(aq)+CO2(aq)+H2O(l).

Expert Solution
Check Mark
Interpretation Introduction

(e)

Interpretation:

The given equation is to be written in total ionic form. The spectator ions are to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is MnO2(s)+4H+(aq)+4Cl(aq)Mn2+(aq)+2Cl(aq)+Cl2(aq)+2H2O(l). The spectator ion is 2Cl. The net ionic equation is MnO2(s)+4H+(aq)+2Cl(aq)Mn2+(aq)+Cl2(aq)+2H2O(l).

Explanation of Solution

The given reaction is shown below.

MnO2(s)+4HCl(aq)MnCl2(aq)+Cl2(aq)+2H2O(l)

The total ionic form of given reaction can be written as shown below.

MnO2(s)+4H+(aq)+4Cl(aq)Mn2+(aq)+2Cl(aq)+Cl2(aq)+2H2O(l)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ion is 2Cl.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

MnO2(s)+4H+(aq)+2Cl(aq)Mn2+(aq)+Cl2(aq)+2H2O(l)

Conclusion

The total ionic form of given reaction is MnO2(s)+4H+(aq)+4Cl(aq)Mn2+(aq)+2Cl(aq)+Cl2(aq)+2H2O(l). The spectator ion is 2Cl. The net ionic equation is MnO2(s)+4H+(aq)+2Cl(aq)Mn2+(aq)+Cl2(aq)+2H2O(l).

Expert Solution
Check Mark
Interpretation Introduction

(f)

Interpretation:

The given equation is to be written in total ionic form. The spectator ions are to be identified. The net ionic equation is to be stated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The ionic compound conducts electricity in the molten state or in solution. The ionic compounds are soluble in water and dissociates into their respective ions.

Answer to Problem 5.31E

The total ionic form of given reaction is 2Ag+(aq)+2NO3(aq)+Cu(s)Cu2+(aq)+2NO3(aq)+2Ag(s). The spectator ion is NO3. The net ionic equation is 2Ag+(aq)+Cu(s)Cu2+(aq)+2Ag(s).

Explanation of Solution

The given reaction is shown below.

2AgNO3(aq)+Cu(s)Cu(NO3)2(aq)+2Ag(s)

The total ionic form of given reaction can be written as shown below.

2Ag+(aq)+2NO3(aq)+Cu(s)Cu2+(aq)+2NO3(aq)+2Ag(s)

The spectator ions are those ions whose identity does not change after the reaction. Thus, the spectator ion is NO3.

The net ionic equation can be expressed by removing the spectator ions. Hence, the net ionic equation is shown below.

2Ag+(aq)+Cu(s)Cu2+(aq)+2Ag(s)

Conclusion

The total ionic form of given reaction is 2Ag+(aq)+2NO3(aq)+Cu(s)Cu2+(aq)+2NO3(aq)+2Ag(s). The spectator ion is NO3. The net ionic equation is 2Ag+(aq)+Cu(s)Cu2+(aq)+2Ag(s).

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Chapter 5 Solutions

Chemistry for Today: General, Organic, and Biochemistry

Ch. 5 - Find the element with the highest oxidation number...Ch. 5 - Find the element with the highest oxidation number...Ch. 5 - For each of the following equations, indicate...Ch. 5 - For each of the following equations, indicate...Ch. 5 - Assign oxidation numbers to each element in the...Ch. 5 - Assign oxidation numbers to each element in the...Ch. 5 - The tarnish of silver objects is a coating of...Ch. 5 - Prob. 5.18ECh. 5 - Prob. 5.19ECh. 5 - Classify each of the reactions represented by the...Ch. 5 - Classify each of the reactions represented by the...Ch. 5 - Prob. 5.22ECh. 5 - Prob. 5.23ECh. 5 - Prob. 5.24ECh. 5 - Prob. 5.25ECh. 5 - Prob. 5.26ECh. 5 - Prob. 5.27ECh. 5 - Consider all of the following ionic compounds to...Ch. 5 - Consider all of the following ionic compounds to...Ch. 5 - Prob. 5.30ECh. 5 - Reactions represented by the following equations...Ch. 5 - Prob. 5.32ECh. 5 - Prob. 5.33ECh. 5 - Prob. 5.34ECh. 5 - Prob. 5.35ECh. 5 - Prob. 5.36ECh. 5 - Prob. 5.37ECh. 5 - Prob. 5.38ECh. 5 - Prob. 5.39ECh. 5 - Prob. 5.40ECh. 5 - Calculate the number of grams of SO2 that must...Ch. 5 - Calculate the mass of limestone (CaCO3) that must...Ch. 5 - Calculate the number of moles of CO2 generated by...Ch. 5 - Calculate the number of grams of bromine (Br2)...Ch. 5 - Prob. 5.45ECh. 5 - Prob. 5.46ECh. 5 - Pure titanium metal is produced by reacting...Ch. 5 - An important metabolic process of the body is the...Ch. 5 - Caproic acid is oxidized in the body as follows:...Ch. 5 - A sample of 4.00g of methane (CH4) is mixed with...Ch. 5 - Nitrogen and oxygen react as follows:...Ch. 5 - Suppose you want to use acetylene (C2H2) as a...Ch. 5 - Ammonia, carbon dioxide, and water vapor react to...Ch. 5 - Prob. 5.55ECh. 5 - The actual yield of a reaction was 11.74g of...Ch. 5 - A product weighing 14.37g was isolated from a...Ch. 5 - Prob. 5.58ECh. 5 - A sample of calcium metal with a mass of 2.00g was...Ch. 5 - Upon heating, mercury (II) oxide undergoes a...Ch. 5 - Prob. 5.61ECh. 5 - Rewrite the following word equation using chemical...Ch. 5 - The element with an electron configuration of...Ch. 5 - Assuming a 100 reaction yield, it was calculated...Ch. 5 - The decomposition of a sample of a compound...Ch. 5 - Prob. 5.66ECh. 5 - Prob. 5.67ECh. 5 - Prob. 5.68ECh. 5 - Prob. 5.69ECh. 5 - Prob. 5.70ECh. 5 - Certain vegetables and fruits, such as potatoes...Ch. 5 - In an ordinary flashlight battery, an oxidation...Ch. 5 - Prob. 5.73ECh. 5 - Prob. 5.74ECh. 5 - Which of the following equations is balanced? a....Ch. 5 - Prob. 5.76ECh. 5 - Prob. 5.77ECh. 5 - What is the oxidation number of sodium in the...Ch. 5 - Prob. 5.79ECh. 5 - Prob. 5.80ECh. 5 - Prob. 5.81ECh. 5 - Prob. 5.82ECh. 5 - Prob. 5.83ECh. 5 - Which of the following species is being oxidized...Ch. 5 - Identify the oxidizing agent and the reducing...Ch. 5 - Prob. 5.86ECh. 5 - Identify the following as an oxidation, a...Ch. 5 - Prob. 5.88ECh. 5 - Prob. 5.89ECh. 5 - Prob. 5.90ECh. 5 - What is the net ionic equation of the following...Ch. 5 - Prob. 5.92ECh. 5 - Prob. 5.93ECh. 5 - The number of grams of hydroegn formed by the...Ch. 5 - In the reaction CaCl2+Na2CO3CaCO3+2NaCl, if...Ch. 5 - Prob. 5.96E
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