The Hydrostatic Paradox II Consider the two lightweight containers shown in Figure 15-48 . As in the previous problem, these containers have equal forces on their bases but contain different weights of water. This is another version of the hydrostatic paradox. (a) Determine the net downward force exerted by the water on container 2. Note that the bases of the containers have an area A base = 24 cm 2 , the annular region has an area A ring = 18 cm 2 , and the depth of the water is 18 cm. (b) Show that your result from part (a) is equal to the weight of the water in container 2. (c) If a hole is poked in the annular region of container 2, how fast will water exit the hole? (d) How high above the hole will the stream of water rise?
The Hydrostatic Paradox II Consider the two lightweight containers shown in Figure 15-48 . As in the previous problem, these containers have equal forces on their bases but contain different weights of water. This is another version of the hydrostatic paradox. (a) Determine the net downward force exerted by the water on container 2. Note that the bases of the containers have an area A base = 24 cm 2 , the annular region has an area A ring = 18 cm 2 , and the depth of the water is 18 cm. (b) Show that your result from part (a) is equal to the weight of the water in container 2. (c) If a hole is poked in the annular region of container 2, how fast will water exit the hole? (d) How high above the hole will the stream of water rise?
The Hydrostatic Paradox II Consider the two lightweight containers shown in Figure 15-48. As in the previous problem, these containers have equal forces on their bases but contain different weights of water. This is another version of the hydrostatic paradox. (a) Determine the net downward force exerted by the water on container 2. Note that the bases of the containers have an area Abase = 24 cm2, the annular region has an area Aring = 18 cm2, and the depth of the water is 18 cm. (b) Show that your result from part (a) is equal to the weight of the water in container 2. (c) If a hole is poked in the annular region of container 2, how fast will water exit the hole? (d) How high above the hole will the stream of water rise?
Helicobacter pylori (H. pylori) is a helically-shaped bacterium that is usually found in the stomach. It burrows through the gastric mucous
lining to establish an infection in the stomach's epithelial cells (see photo). Approximately 90% of the people infected with H. pylori will
never experience symptoms. Others may develop peptic ulcers and show symptoms of chronic gastritis. The method of motility of H.
pylori is a prokaryotic flagellum attached to the back of the bacterium that rigidly rotates like a propeller on a ship. The flagellum is
composed of proteins and is approximately 40.0 nm in diameter and can reach rotation speeds as high as 1.50 x 103 rpm. If the speed
of the bacterium is 10.0 μm/s, how far has it moved in the time it takes the flagellum to rotate through an angular displacement of 5.00
* 10² rad?
Zina Deretsky, National Science
Foundation/Flickr
H. PYLORI CROSSING MUCUS LAYER OF STOMACH
H.pylori Gastric Epithelial
mucin cells
gel
Number
i
318
Units
um
H.pylori…
T1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.
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