Microbiology: An Introduction
12th Edition
ISBN: 9780321929150
Author: Gerard J. Tortora, Berdell R. Funke, Christine L. Case
Publisher: PEARSON
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Chapter 15, Problem 6R
Summary Introduction
To review:
How the Shiga toxin enters a human cell and inhibits protein synthesis.
Concept introduction:
Microorganisms that have the ability to cause infectious diseases are called as pathogens. Illness in an individual is caused either by disturbing the normal
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Explain:
Healthy Cell Function Overview→ Briefly describe how a healthy cell usually works: metabolism (ATP production), pH balance, glycogen storage, ion transport, enzymes, etc.
Gene Mutation and Genetics Part→ Focus on the autosomal recessive mutation and explain:
How gene mutation affects the cell.
How autosomal inheritance works.
Compare the normal and mutated gene sequences simply. → Talk about possible consequences of a faulty hydrolytic enzyme.
Can you fill out those terms
Explain down bellow what happens to the cell:
Decreased pH in mitochondria
Increased ATP
Decreased pH in cytosol
Increased hydrolysis
Decreasing glycogen and triglycerides
Increased MAP kinase activity
Poor ion transport → For each one:→ What normally happens?→ What is wrong now?→ How does it mess up the cell?
Chapter 15 Solutions
Microbiology: An Introduction
Ch. 15 - Compare pathogenicity with virulence.Ch. 15 - How are capsules and cell wall components related...Ch. 15 - Prob. 3RCh. 15 - Explain how drugs that bind each of the following...Ch. 15 - Prob. 5RCh. 15 - Prob. 6RCh. 15 - Prob. 7RCh. 15 - Which of the following genera is the most...Ch. 15 - How can viruses and protozoa avoid being killed by...Ch. 15 - Prob. 10R
Ch. 15 - The removal of plasmids reduces virulence in which...Ch. 15 - Prob. 2MCQCh. 15 - Prob. 3MCQCh. 15 - All of the following can occur during bacterial...Ch. 15 - The ID50 for Campylobacter sp. is 500 cells; the...Ch. 15 - Prob. 6MCQCh. 15 - A drug that binds to mannose on human cells would...Ch. 15 - The earliest smallpox vaccines were infected...Ch. 15 - Prob. 9MCQCh. 15 - Which of the following statements is true? a. The...Ch. 15 - Prob. 1ACh. 15 - Prob. 3ACh. 15 - How do each of the following strategies contribute...Ch. 15 - On July 8, a woman was given an antibiotic for...Ch. 15 - Explain whether each of the following examples is...Ch. 15 - Cancer patients undergoing chemotherapy are...
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- 5G JA ATTC 3 3 CTIA A1G5 5 GAAT I I3 3 CTIA AA5 Fig. 5-3: The Eco restriction site (left) would be cleaved at the locations indicated by the arrows. However, a SNP in the position shown in gray (right) would prevent cleavage at this site by EcoRI One of the SNPs in B. rapa is found within the Park14 locus and can be detected by RFLP analysis. The CT polymorphism is found in the intron of the Bra013780 gene found on Chromosome 1. The Park14 allele with the "C" in the SNP has two EcoRI sites and thus is cleaved twice by EcoRI If there is a "T" in that SNP, one of the EcoRI sites is altered, so the Park14 allele with the T in the SNP has only one EcoRI site (Fig. 5-3). Park14 allele with SNP(C) Park14 allele with SNPT) 839 EcoRI 1101 EcoRI 839 EcoRI Fig. 5.4: Schematic restriction maps of the two different Park14 alleles (1316 bp long) of B. rapa. Where on these maps is the CT SNP located? 90 The primers used to amplify the DNA at the Park14 locus (see Fig. 5 and Table 3 of Slankster et…arrow_forwardFrom your previous experiment, you found that this enhancer activates stripe 2 of eve expression. When you sequence this enhancer you find several binding sites for the gap gene, Giant. To test how Giant interacts with eve, you decide to remove all of the Giant binding sites from the eve enhancer. What results do you expect to see with respect to eve expression?arrow_forwardWhat experiment could you do to see if the maternal gene, bicoid, is sufficient to form anterior fates?arrow_forward
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