Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
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Chapter 15, Problem 61AE
Interpretation Introduction

Interpretation:

The new molarity when 10.0 mL of 12 M HCl is diluted by addition of 250.0 mL water has to be calculated.

Concept Introduction:

The dilution formula is given as follows:

  M1V1=M2V2

Here,

M1 denotes molarity of  initial solution before dilution.

V1 denotes the volume before dilution.

M2 denotes molarity of final solution after dilution.

V2 denotes volume after dilution.

The expression to evaluate pH is as follows:

  pH=log[H+]

Here,

[H+] denotes concentration of H+ ions.

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Chapter 15 Solutions

Foundations of College Chemistry, Binder Ready Version

Ch. 15 - Prob. 3RQCh. 15 - Prob. 4RQCh. 15 - Prob. 5RQCh. 15 - Prob. 6RQCh. 15 - Prob. 7RQCh. 15 - Prob. 8RQCh. 15 - Prob. 9RQCh. 15 - Prob. 10RQCh. 15 - Prob. 11RQCh. 15 - Prob. 12RQCh. 15 - Prob. 13RQCh. 15 - Prob. 14RQCh. 15 - Prob. 15RQCh. 15 - Prob. 16RQCh. 15 - Prob. 17RQCh. 15 - Prob. 18RQCh. 15 - Prob. 19RQCh. 15 - Prob. 20RQCh. 15 - Prob. 21RQCh. 15 - Prob. 22RQCh. 15 - Prob. 23RQCh. 15 - Prob. 24RQCh. 15 - Prob. 25RQCh. 15 - Prob. 26RQCh. 15 - Prob. 27RQCh. 15 - Prob. 28RQCh. 15 - Prob. 1PECh. 15 - Prob. 2PECh. 15 - Prob. 3PECh. 15 - Prob. 4PECh. 15 - Prob. 5PECh. 15 - Prob. 6PECh. 15 - Prob. 7PECh. 15 - Prob. 8PECh. 15 - Prob. 9PECh. 15 - Prob. 10PECh. 15 - Prob. 11PECh. 15 - Prob. 12PECh. 15 - Prob. 13PECh. 15 - Prob. 14PECh. 15 - Prob. 15PECh. 15 - Prob. 16PECh. 15 - Prob. 17PECh. 15 - Prob. 18PECh. 15 - Prob. 19PECh. 15 - Prob. 20PECh. 15 - Prob. 21PECh. 15 - Prob. 22PECh. 15 - Prob. 23PECh. 15 - Prob. 24PECh. 15 - Prob. 25PECh. 15 - Prob. 26PECh. 15 - Prob. 27PECh. 15 - Prob. 28PECh. 15 - Prob. 29PECh. 15 - Prob. 30PECh. 15 - Prob. 31PECh. 15 - Prob. 32PECh. 15 - Prob. 33PECh. 15 - Prob. 34PECh. 15 - Prob. 35PECh. 15 - Prob. 36PECh. 15 - Prob. 37PECh. 15 - Prob. 38PECh. 15 - Prob. 39PECh. 15 - Prob. 40PECh. 15 - Prob. 41PECh. 15 - Prob. 42PECh. 15 - Prob. 43PECh. 15 - Prob. 44PECh. 15 - Prob. 45AECh. 15 - Prob. 46AECh. 15 - Prob. 47AECh. 15 - Prob. 48AECh. 15 - Prob. 49AECh. 15 - Prob. 50AECh. 15 - Prob. 51AECh. 15 - Prob. 52AECh. 15 - Prob. 53AECh. 15 - Prob. 54AECh. 15 - Prob. 55AECh. 15 - Prob. 56AECh. 15 - Prob. 57AECh. 15 - Prob. 58AECh. 15 - Prob. 59AECh. 15 - Prob. 60AECh. 15 - Prob. 61AECh. 15 - Prob. 62AECh. 15 - Prob. 63AECh. 15 - Prob. 64AECh. 15 - Prob. 65AECh. 15 - Prob. 66AECh. 15 - Prob. 67AECh. 15 - Prob. 68AECh. 15 - Prob. 69AECh. 15 - Prob. 70AECh. 15 - Prob. 71AECh. 15 - Prob. 72AECh. 15 - Prob. 73CECh. 15 - Prob. 74CE
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY