Chapter 15, Problem 38PE

Interpretation Introduction

Interpretation:

Volume of ${\text{H}}_2$ obtained from $\text{200 mL}$ of $\text{0}\text{.350 M HCl}$ has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example, $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$.

The formula to calculate molar mass from number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

The formula to compute volume as per ideal gas equation is written as follows:

  $V=\frac{nRT}{P}$

Here,

$\text{R}$ represents universal gas constant.

$V$ denotes volume.

$n$ denotes moles.

$T$ denotes temperature.

$P$ denotes pressure.