Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 15, Problem 50P
(a)
To determine
The frequency by which the knees are bent so that the baby is able to bounce with maximum amplitude and minimum effort.
(b)
To determine
The minimum amplitude of oscillation required.
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Chapter 15 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 15.1 - A block on the end of a spring is pulled to...Ch. 15.2 - Consider a graphical representation (Fig. 15.3) of...Ch. 15.2 - shows two curves representing particles undergoing...Ch. 15.2 - An object of mass m is hung from a spring and set...Ch. 15.4 - The ball in Figure 15.13 moves in a circle of...Ch. 15.5 - The grandfather clock in the opening storyline...Ch. 15 - Prob. 1OQCh. 15 - Prob. 2OQCh. 15 - Prob. 3OQCh. 15 - Prob. 4OQ
Ch. 15 - Prob. 5OQCh. 15 - Prob. 6OQCh. 15 - Prob. 7OQCh. 15 - Prob. 8OQCh. 15 - Prob. 9OQCh. 15 - Prob. 10OQCh. 15 - Prob. 11OQCh. 15 - Prob. 12OQCh. 15 - Prob. 13OQCh. 15 - Prob. 14OQCh. 15 - Prob. 15OQCh. 15 - Prob. 16OQCh. 15 - Prob. 17OQCh. 15 - Prob. 1CQCh. 15 - Prob. 2CQCh. 15 - Prob. 3CQCh. 15 - Prob. 4CQCh. 15 - Prob. 5CQCh. 15 - Prob. 6CQCh. 15 - Prob. 7CQCh. 15 - Prob. 8CQCh. 15 - Prob. 9CQCh. 15 - Prob. 10CQCh. 15 - Prob. 11CQCh. 15 - Prob. 12CQCh. 15 - Prob. 13CQCh. 15 - A 0.60-kg block attached to a spring with force...Ch. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - Prob. 4PCh. 15 - The position of a particle is given by the...Ch. 15 - A piston in a gasoline engine is in simple...Ch. 15 - Prob. 7PCh. 15 - Prob. 8PCh. 15 - Prob. 9PCh. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12PCh. 15 - Review. A particle moves along the x axis. It is...Ch. 15 - Prob. 14PCh. 15 - A particle moving along the x axis in simple...Ch. 15 - The initial position, velocity, and acceleration...Ch. 15 - Prob. 17PCh. 15 - Prob. 18PCh. 15 - Prob. 19PCh. 15 - You attach an object to the bottom end of a...Ch. 15 - Prob. 21PCh. 15 - Prob. 22PCh. 15 - Prob. 23PCh. 15 - Prob. 24PCh. 15 - Prob. 25PCh. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - A simple harmonic oscillator of amplitude A has a...Ch. 15 - Review. A 65.0-kg bungee jumper steps off a bridge...Ch. 15 - Review. A 0.250-kg block resting on a...Ch. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - A seconds pendulum is one that moves through its...Ch. 15 - A simple pendulum makes 120 complete oscillations...Ch. 15 - A particle of mass m slides without friction...Ch. 15 - A physical pendulum in the form of a planar object...Ch. 15 - Prob. 38PCh. 15 - Prob. 39PCh. 15 - Consider the physical pendulum of Figure 15.16....Ch. 15 - Prob. 41PCh. 15 - Prob. 42PCh. 15 - Prob. 43PCh. 15 - Prob. 44PCh. 15 - A watch balance wheel (Fig. P15.25) has a period...Ch. 15 - Prob. 46PCh. 15 - Prob. 47PCh. 15 - Show that the time rate of change of mechanical...Ch. 15 - Show that Equation 15.32 is a solution of Equation...Ch. 15 - Prob. 50PCh. 15 - Prob. 51PCh. 15 - Prob. 52PCh. 15 - Prob. 53PCh. 15 - Considering an undamped, forced oscillator (b =...Ch. 15 - Prob. 55PCh. 15 - Prob. 56APCh. 15 - An object of mass m moves in simple harmonic...Ch. 15 - Prob. 58APCh. 15 - Prob. 59APCh. 15 - Prob. 60APCh. 15 - Four people, each with a mass of 72.4 kg, are in a...Ch. 15 - Prob. 62APCh. 15 - Prob. 63APCh. 15 - An object attached to a spring vibrates with...Ch. 15 - Prob. 65APCh. 15 - Prob. 66APCh. 15 - A pendulum of length L and mass M has a spring of...Ch. 15 - A block of mass m is connected to two springs of...Ch. 15 - Prob. 69APCh. 15 - Prob. 70APCh. 15 - Review. A particle of mass 4.00 kg is attached to...Ch. 15 - Prob. 72APCh. 15 - Prob. 73APCh. 15 - Prob. 74APCh. 15 - Prob. 75APCh. 15 - Review. A light balloon filled with helium of...Ch. 15 - Prob. 78APCh. 15 - A particle with a mass of 0.500 kg is attached to...Ch. 15 - Prob. 80APCh. 15 - Review. A lobstermans buoy is a solid wooden...Ch. 15 - Prob. 82APCh. 15 - Prob. 83APCh. 15 - A smaller disk of radius r and mass m is attached...Ch. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CPCh. 15 - A light, cubical container of volume a3 is...
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- A grandfather clock has a pendulum length of 0.7 m and mass bob of 0.4 kg. A mass of 2 kg falls 0.8 m in seven days to keep the amplitude (from equilibrium) of the pendulum oscillation steady at 0.03 rad. What is the Q of the system?arrow_forwardIf the amplitude of a damped oscillator decreases to 1/e of its initial value after n periods, show that the frequency of the oscillator must be approximately [1 − (8π2n2)−1] times the frequency of the corresponding undamped oscillator.arrow_forwardIf a car has a suspension system with a force constant of 5.00104 N/m , how much energy must the car’s shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m?arrow_forward
- A block of unknown mass is attached to a spring with a spring constant of 6.50 N/m and undergoes simple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 30.0 cm/s. Calculate (a) the mass of the block, (b) the period of the motion, and (c) the maximum acceleration of the block.arrow_forwardThe total energy of a simple harmonic oscillator with amplitude 3.00 cm is 0.500 J. a. What is the kinetic energy of the system when the position of the oscillator is 0.750 cm? b. What is the potential energy of the system at this position? c. What is the position for which the potential energy of the system is equal to its kinetic energy? d. For a simple harmonic oscillator, what, if any, are the positions for which the kinetic energy of the system exceeds the maximum potential energy of the system? Explain your answer. FIGURE P16.73arrow_forwardAn automobile with a mass of 1000 kg, including passengers, settles 1.0 cm closer to the road for every additional 100 kg of passengers. It is driven with a constant horizontal component of speed 20 km/h over a washboard road with sinusoidal bumps. The amplitude and wavelength of the sine curve are 5.0 cm and 20 cm, respectively. The distance between the front and back wheels is 2.4 m. Find the amplitude of oscillation of the automobile, assuming it moves vertically as an undamped driven harmonic oscillator. Neglect the mass of the wheels and springs and assume that the wheels are always in contact with the road.arrow_forward
- A particle of mass m moving in one dimension has potential energy U(x) = U0[2(x/a)2 (x/a)4], where U0 and a are positive constants. (a) Find the force F(x), which acts on the particle. (b) Sketch U(x). Find the positions of stable and unstable equilibrium. (c) What is the angular frequency of oscillations about the point of stable equilibrium? (d) What is the minimum speed the particle must have at the origin to escape to infinity? (e) At t = 0 the particle is at the origin and its velocity is positive and equal in magnitude to the escape speed of part (d). Find x(t) and sketch the result.arrow_forwardWhich of the following statements is not true regarding a massspring system that moves with simple harmonic motion in the absence of friction? (a) The total energy of the system remains constant. (b) The energy of the system is continually transformed between kinetic and potential energy. (c) The total energy of the system is proportional to the square of the amplitude. (d) The potential energy stored in the system is greatest when the mass passes through the equilibrium position. (e) The velocity of the oscillating mass has its maximum value when the mass passes through the equilibrium position.arrow_forwardShow that the time rate of change of mechanical energy for a damped, undriven oscillator is given by dE/dt = bv2 and hence is always negative. To do so, differentiate the expression for the mechanical energy of an oscillator, E=12mv2+12kx2, and use Equation 12.28.arrow_forward
- Show that angular frequency of a physical pendulum phy=mgrCM/I (Eq. 16.33) equals the angular frequency of a simple pendulum smp=g/, (Eq. 16.29) in the case of a particle at the end of a string of length .arrow_forwardIf a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes 2 times as large. (c) It becomes half as large. (d) It becomes 1/2 times as large. (e) It remains the same.arrow_forwardIn an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.arrow_forward
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