Chapter 15, Problem 48P

To determine

To find: Required area of supply electricity.

Answer to Problem 48P

  $61.11{\text{m}}^{\text{2}}$

Explanation of Solution

Given Data:

Power of solar cell $=4\text{0}{\text{W/m}}^{\text{2}}$

Sun shine about $9$ h/day needs $=22$ kWh/day

Formula used: $\text{energy generate = power×time}$

Calculation:

Energy generate by solar cells $=4\text{0}{\text{W/m}}^{\text{2}}\times 9\text{h}=360\text{W}\cdot {\text{h/m}}^{\text{2}}$

  ${\text{E}}_{\text{generate}}=360\times {10}^{-3}\text{kW}\cdot {\text{h/m}}^{\text{2}}$

Hence, required area $=\frac{22}{360}\times {10}^3$

Required area of roof $=61.11{\text{m}}^2$