Chapter 15, Problem 18P

To determine

To find : The efficiency of the engine.

Answer to Problem 18P

  $0.099$

Explanation of Solution

Given:

Input energy $22\text{kcal}=22\times 4.2\times {10}^3\text{J}$

Out put $=9200$ J

Formula Used :

Efficiency $=\frac{\text{out put}}{\text{input}}$

Calculation :

Efficiency $=\frac{9200}{22\times 4.2\times {10}^3}$

Efficiency $=\frac{92000}{22\times 42\times {10}^3}=\frac{92}{22\times 42}=0.099$

Efficiency $=0.099$