Chapter 15, Problem 1P

(a)

To determine

The change in the internal energy of the gas.

Answer to Problem 1P

The change in the internal energy of the gas is $0\text{J}$ .

Explanation of Solution

Given info:

The change in the temperature is, $\Delta T=0°\text{C}$ .

Formula Used:

The expression to calculate the change in the internal energy of the gas is,

  $\Delta U=mc\Delta T$

Here, m is the mass of the gas, c is the specific heat of the gas.

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}\Delta U=mc\left(0°\text{C}\right)\\ =0\text{J}\end{array}$

Conclusion:

Thus, the change in the internal energy of the gas is $0\text{J}$ .

(b)

To determine

The heat absorbed during expansion of gas.

Answer to Problem 1P

The heat absorbed during expansion of the gas is $3.40\times {10}^3\text{J}$ .

Explanation of Solution

Given info:

The work done by the gas in expansion process is, $W=3.40\times {10}^3\text{J}$ .

Formula Used:

The expression to calculate the heat absorbed during expansion of the gas is,

  $Q=\Delta U+W$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}Q=0\text{J}+3.40\times {10}^3\text{J}\\ =3.40\times {10}^3\text{J}\end{array}$

Conclusion:

Thus, the heat absorbed during expansion of the gas is $3.40\times {10}^3\text{J}$ .