![Physics: Principles with Applications](https://www.bartleby.com/isbn_cover_images/9780130606204/9780130606204_largeCoverImage.gif)
Concept explainers
(a)
The rank of four aces and a king.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 46P
The four aces and a king ranks second among all the option.
Explanation of Solution
Given:
The given that rank of the following five-card hand in order of increasing the probability.
Calculation:
Calculate the rank of the four aces and a king.
There are four different combination that satisfy this particular microstate.
Therefore, the four aces and a king ranks second among all the option.
(b)
The rank of six of hearts, eight of diamonds, queen of clubs, three of hearts, jack of spades probability.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 46P
The six of hearts, eight of diamonds, queen of clubs, three of hearts, jack of spades ranks first because it has the lowest probability.
Explanation of Solution
Given:
The given that rank of the following five-card hand in order of increasing probability.
Calculation:
Calculate the probability,
Since there is only one of very card this microstate has one microstate.
Therefore, the six of hearts, eight of diamonds, queen of clubs, three of hearts, jack of spades ranks first because it has the lowest probability.
(c)
The rank of two jacks, two queen and an ace.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 46P
The two jacks, two queen and an ace is
Explanation of Solution
Given:
The given that rank of the following five-card hand in order of increasing probability.
Calculation:
Calculate the probability,
There are four possible ace combination and six possible combination for both and queen.
The two jacks, two queen, and an ace is,
Therefore, the two jacks, two queen, and an ace has
(d)
The rank of any hand having no two equal-value cards.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 46P
The hand having no two equal-value cards ranks last.
Explanation of Solution
Given:
The given that rank of the following five-card hand in order of increasing probability.
Calculation:
Calculate the probability,
This has the greatest possibility because the first card can be any card in the deck,
Therefore, the hand having no two equal-value cards ranks last.
Chapter 15 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Microbiology: An Introduction
Chemistry: The Central Science (14th Edition)
Microbiology: An Introduction
Anatomy & Physiology (6th Edition)
Campbell Biology (11th Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- No chatgpt pls will upvotearrow_forwardSARET CRKS AUTOWAY 12. A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff? 13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming no air resistance, what is the speed of the ball just before it strikes the ground? 14. Estimate (a) how long it took King Kong to fall straight down from the top of the Empire State Building (280m high), and (b) his velocity just before "landing". Useful equations For Constant Velocity: V => D X = V₁t + Xo For Constant Acceleration: Vr = V + at X = Xo+Vot + v=V+2a(X-Xo) \prom = V +V V velocity t = time D Distance X = Final Position Xo Initial Position V = Final Velocity Vo Initial Velocity a = acceleration For free fall Yf = Final Position Yo Initial Position g = 9.80 m $2 For free fall: V = V + gt Y=Yo+Vo t + +gt V,² = V₁²+2g (Y-Yo) V+Vo Vprom= 2 6arrow_forwardSolve the problemsarrow_forward
- A 11 kg weight is attached to a spring with constant k = 99 N/m and subjected to an external force F(t) =-704 sin(5t). The weight is initially displaced 4 meters above equilibrium and given an upward velocity of 5 m/s. Find its displacement for t> 0. y(t) וןarrow_forward7. A race car accelerates from rest to 55 m s-1 in 5.0 seconds. The acceleration of the car Is m s-² 8. An object's speed increases uniformly from 10.5 km per hour to 99.8 km per hour in 2.41 seconds. Calculate the acceleration in m s-2 and express your answer to three significant figures. 9. The acceleration-time graph of a car is shown below. The initial speed of the car is 5.0 m s-1. # Acceleration (ms) 12 8.0- 4.0- 2.0 4.0 6.0 Time (s) Calculate the velocity of the car at t = 4.0 s. 3arrow_forwardNo chatgpt pls will upvotearrow_forward
- No chatgpt pls will upvotearrow_forwardProblem Seven. A football receiver running straight downfield at 5.60 m/s is 11.5 m in front of the quarterback when a pass is thrown downfield at an angle of 35.0° horizon. above the 8.) If the receiver never changes speed and the ball is caught at the same height from which it was thrown, find the distance between the quarterback and the receiver when the catch is made. (A) 21.3 (B) 17.8 (C) 18.8 (D) 19.9 (E) 67.5arrow_forwardPlease solve and answer the question correctly please. Thank you!!arrow_forward
- Please solve and answer the question correctly please. Thank you!!arrow_forwardPlease view both photos, and answer the question correctly please. Thank you!!arrow_forwardA thrown brick hits a window, but doesn't break it. Instead it reverses direction and ends down on the ground below the window. Since the brick didn't break the glass, we know: О The force of the brick on the glass > the force of the glass on the brick. О The force of the brick on the glass the force of the glass on the brick. = О The force of the brick on the glass < the force of the glass on the brick. О The brick didn't slow down as it broke the glass.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)