Chapter 15, Problem 16STP

Interpretation Introduction

Interpretation:

The specific heat of aluminium is to be calculated if amount and rise in temperature are given.

Concept introduction:

Specific heat is defined as quantity of heat required to raise the temperature of one gram substance by one Kelvin. It is represented by ‘c’.

Answer to Problem 16STP

C

Explanation of Solution

The quantity of heat required can be calculated by using formula:

$\begin{array}{l}q=mc\Delta T\\ whereqisquantityofheatabsorbed\\ m=givenmass\\ \Delta T=riseintemperature\\ cisspecificheat\\ \therefore c=\frac{q}{m\Delta T}\end{array}$

Given data:

$\begin{array}{l}m=3g\\ \Delta T=662-20\\ =642°C\\ q=1728J\end{array}$

Substituting the values in formula:

$\begin{array}{c}c=\frac{q}{m\Delta T}\\ =\frac{1728}{3\times 642}\\ =0.897J/g-°C\end{array}$

Conclusion

Thus specific heat of aluminium is $0.897J/g-°C$.