Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Question
Chapter 15, Problem 116A
a.
Interpretation Introduction
Interpretation:
The naming of the given molecular compound S2Cl2 is to be done.
Concept introduction:
The positive ion of the compound is written normally while the negative ion is written according to IUPAC convention. Prefixes and suffixes are added according to numbers.
a.
Expert Solution
Answer to Problem 116A
The name of the given compound is disulphur dichloride.
Explanation of Solution
The presence of 2 atoms of each element in the molecule is the reason for the use of di- prefix.
b.
Interpretation Introduction
Interpretation:
The naming of the given molecular compound SO3 is to be done.
Concept introduction:
The positive ion of the compound is written normally while the negative ion is written according to IUPAC convention. Prefixes and suffixes are added according to numbers.
b.
Expert Solution
Answer to Problem 116A
The name of the given compound is Sulphur trioxide.
Explanation of Solution
Single atom of Sulphur is present, so it is written without prefix and 3 atoms of oxygen means tri- prefix is used for oxygen.
c.
Interpretation Introduction
Interpretation:
The naming of the given molecular compound CS2 is to be done.
Concept introduction:
The positive ion of the compound is written normally while the negative ion is written according to IUPAC convention. Prefixes and suffixes are added according to numbers.
c.
Expert Solution
Answer to Problem 116A
The name of the given compound is carbon disulphide.
Explanation of Solution
Single atom of carbon is present, so it is written without prefix and 2 atoms of oxygen means di- prefix is used for oxygen.
d.
Interpretation Introduction
Interpretation:
The naming of the given molecular compound P4O10 is to be done.
Concept introduction:
The positive ion of the compound is written normally while the negative ion is written according to IUPAC convention. Prefixes and suffixes are added according to numbers.
d.
Expert Solution
Answer to Problem 116A
The name of the given compound is bis- (diphosphorus pentoxide).
Explanation of Solution
2 atoms of phosphorus are present, so it is written with di- prefix and 5 atoms of oxygen means pent(a)- prefix is used. Also, the compound is a dimer so bis- prefix is used.
Chapter 15 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
Ch. 15.1 - Prob. 1PPCh. 15.1 - Prob. 2PPCh. 15.1 - Prob. 3PPCh. 15.1 - Prob. 4PPCh. 15.1 - Prob. 5PPCh. 15.1 - Prob. 6PPCh. 15.1 - Prob. 7SSCCh. 15.1 - Prob. 8SSCCh. 15.1 - Prob. 9SSCCh. 15.1 - Prob. 10SSC
Ch. 15.1 - Prob. 11SSCCh. 15.2 - Prob. 12PPCh. 15.2 - Prob. 13PPCh. 15.2 - Prob. 14PPCh. 15.2 - Prob. 15PPCh. 15.2 - Prob. 16SSCCh. 15.2 - Prob. 17SSCCh. 15.2 - Prob. 18SSCCh. 15.2 - Prob. 19SSCCh. 15.2 - Prob. 20SSCCh. 15.2 - Prob. 21SSCCh. 15.2 - Prob. 22SSCCh. 15.3 - Prob. 23PPCh. 15.3 - Prob. 24PPCh. 15.3 - Prob. 25PPCh. 15.3 - Prob. 26SSCCh. 15.3 - Prob. 27SSCCh. 15.3 - Prob. 28SSCCh. 15.3 - Prob. 29SSCCh. 15.3 - Prob. 30SSCCh. 15.3 - Prob. 31SSCCh. 15.4 - Prob. 32PPCh. 15.4 - Prob. 33PPCh. 15.4 - Prob. 34PPCh. 15.4 - Prob. 35PPCh. 15.4 - Prob. 36PPCh. 15.4 - Prob. 37PPCh. 15.4 - Prob. 38SSCCh. 15.4 - Prob. 39SSCCh. 15.4 - Prob. 40SSCCh. 15.4 - Prob. 41SSCCh. 15.4 - Prob. 42SSCCh. 15.4 - Prob. 43SSCCh. 15.5 - Prob. 44PPCh. 15.5 - Prob. 45PPCh. 15.5 - Prob. 46PPCh. 15.5 - Prob. 47PPCh. 15.5 - Prob. 48SSCCh. 15.5 - Prob. 49SSCCh. 15.5 - Prob. 50SSCCh. 15.5 - Prob. 51SSCCh. 15.5 - Prob. 52SSCCh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Metallurgy A 25.0-g bolt made of an alloy...Ch. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - How many joules of heat are lost by 3580 kg of...Ch. 15 - Swimming Pool A swimming pool measuring 20.0m12.5m...Ch. 15 - How much heat is absorbed by a 44.7-g piece of...Ch. 15 - Prob. 77ACh. 15 - Alloys When a 58.8-g piece of hot alloy is placed...Ch. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - sUse information from Figure 15.24 to calculate...Ch. 15 - Agriculture Water is sprayed on oranges during...Ch. 15 - Grilling What mass of propane (C3H8) must be...Ch. 15 - Heating with Coal How much heat is liberated...Ch. 15 - How much heat is evolved when 1255 g of water...Ch. 15 - A sample of ammonia (Hsolid=5.66kJ/mol)...Ch. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Heat was added consistently to a sample of water...Ch. 15 - Bicycling Describe the energy conversions that...Ch. 15 - Hiking Imagine that on a cold day you are planning...Ch. 15 - Differentiate between the enthalpy of formation of...Ch. 15 - Analyze both of the images in Figure 15.27 in...Ch. 15 - Apply Phosphorus trichloride is a starting...Ch. 15 - Calculate Suppose that two pieces of iron, one...Ch. 15 - Prob. 111ACh. 15 - sample of natural gas is analyzed and found to...Ch. 15 - Prob. 113ACh. 15 - Prob. 114ACh. 15 - Prob. 115ACh. 15 - Prob. 116ACh. 15 - Prob. 117ACh. 15 - Prob. 118ACh. 15 - Prob. 119ACh. 15 - Prob. 120ACh. 15 - Prob. 121ACh. 15 - Prob. 122ACh. 15 - Prob. 123ACh. 15 - Prob. 124ACh. 15 - Prob. 125ACh. 15 - Prob. 126ACh. 15 - Prob. 127ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STPCh. 15 - Prob. 12STPCh. 15 - Prob. 13STPCh. 15 - Prob. 14STPCh. 15 - Prob. 15STPCh. 15 - Prob. 16STPCh. 15 - Prob. 17STPCh. 15 - Prob. 18STP
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