Chapter 15, Problem 67A

Metallurgy A 25.0-g bolt made of an alloy absorbed250 J of heat as its temperature changed from 25.0°C to78.0°C. What is the specific heat of the alloy?

Interpretation Introduction

Interpretation:

The specific heat of alloy is to be calculated for given amount and rise in temperature.

Concept introduction:

Specific heat is defined as quantity of heat required to raise the temperature of one gram substance by one Kelvin. It is represented by ‘c’.

Answer to Problem 67A

The specific heat of alloy is $0.189J/g-°C$

Explanation of Solution

The quantity of heat required can be calculated by using formula:

$\begin{array}{l}q=mc\Delta T\\ whereqisquantityofheatabsorbed\\ m=givenmass\\ \Delta T=riseintemperature\\ cisspecificheat\\ \therefore c=\frac{q}{m\Delta T}\end{array}$

Given data:

$\begin{array}{l}m=25.0g\\ \Delta T=78.0-25.0\\ =53.0°C\\ q=250J\end{array}$

Substituting the values in formula:

$\begin{array}{c}c=\frac{q}{m\Delta T}\\ =\frac{250}{25\times 53}\\ =0.189J/g-°C\end{array}$

Conclusion

Thus specific heat of alloy is $0.189J/g-°C$.