Chapter 15, Problem 63A

Interpretation Introduction

Interpretation:

The energy absorbed in joules in a process that absorbs 0.5720 kcal is to be calculated.

Concept introduction:

The given amount of heat is to be converted into energy.

The conversion factor is:

$\begin{array}{l}1kcal=1000cal\\ and1cal=4.184J\end{array}$

Answer to Problem 63A

$0.5720kcal=2393.2J$

Explanation of Solution

As, $\begin{array}{l}1kcal=1000cal\\ and1cal=4.184J\end{array}$

Therefore,

$\begin{array}{l}0.5720kcal=0.5720kcal\times \frac{1000cal}{1kcal}\times \frac{4.184J}{1cal}\\ =2393.2J\end{array}$