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(a)
Interpretation:
The
Concept introduction:
Dienes are the compounds that contain carbon-carbon double bonds. The term conjugated dienes is used when the double bonds are present alternatively in a hydrocarbon chain. The mathematical function that describes the wave like behavior of the electron in a molecule is expressed by molecular orbital. The physical and chemical properties are found with the help of molecular orbital.
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Answer to Problem 15.1P
The bonding molecular orbitals are
The anti-bonding molecular orbitals are
The molecular orbitals of conjugated
Explanation of Solution
In
The three bonding molecular orbitals are
The three anti bonding molecular orbitals are
The sketch showing the molecular orbital of conjugated
Figure 1
The three bonding molecular orbitals are
The three anti bonding molecular orbitals are
The sketch showing the molecular orbital of conjugated
(b)
Interpretation:
The total number of nodes in the
Concept introduction:
The term conjugated dienes is used when the double bonds are present alternatively in a hydrocarbon chain. The mathematical function that describes the wave like behavior of an electron in a molecule is expressed by molecular orbital. The molecular orbital contains nodes and lobes. Nodes are the regions in the molecular orbital of conjugated system in which the adjoining orbital lobes undergoes a phase change.
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Answer to Problem 15.1P
The total number of nodes that the molecular orbital (MOs) of conjugated
Explanation of Solution
There is no change of phase occurs in lobes in the
There is one change of phase occurs in lobes in the
There is two change of phase occurs in lobes in the
There are four change of phase occurs in lobes in the
There are five change of phase occurs in lobes in the
There are six change of phase occurs in lobes in the
The number of nodes that molecular orbital (MOs) of conjugated
Molecular Orbital | Number of Nodes |
Zero | |
One | |
Two | |
Three | |
Four | |
Five |
The number of nodes that molecular orbital (MOs) of conjugated
(c)
Interpretation:
The position of the nodes in
Concept introduction:
The term conjugated dienes is used when the double bonds are present alternatively in a hydrocarbon chain. The mathematical function that describes the wave like behavior of the electron in a molecule is expressed by molecular orbital. The molecular orbital contains nodes and lobes. Nodes are the regions in the molecular orbital of conjugated system in which the adjoining orbital lobes undergoes a phase change.
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Answer to Problem 15.1P
The position of the nodes in
Explanation of Solution
There is no change of phase occurs in lobes in the
.
The sketch of
Figure 2
There is one change of phase occurs in lobes in the
The sketch of
Figure 3
There are 6 change of phase occurs in lobes in the
The
The sketch of
Figure 4
The position of the nodes in
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Chapter 15 Solutions
Organic Chemistry
- Explanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forward
- Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forward
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- 2. Propose a mechanism for this reaction. ہلی سے ملی N H (excess)arrow_forwardSteps and explanationn please.arrow_forwardProblem 5-48 Assign R or S configurations to the chirality centers in ascorbic acid (vitamin C). OH H OH HO CH2OH Ascorbic acid O H Problem 5-49 Assign R or S stereochemistry to the chirality centers in the following Newman projections: H Cl H CH3 H3C. OH H3C (a) H H H3C (b) CH3 H Problem 5-52 Draw the meso form of each of the following molecules, and indicate the plane of symmetry in each: OH OH (a) CH3CHCH2CH2CHCH3 CH3 H3C. -OH (c) H3C CH3 (b) Problem 5-66 Assign R or S configurations to the chiral centers in cephalexin, trade-named Keflex, the most widely prescribed antibiotic in the United States. H2N H IHH S Cephalexin N. CH3 CO₂Harrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
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