To solve: The function is defined on the interval ,
a. Graph ,
indicating the area under from 3 to 7.
Answer to Problem 20AYU
a.
Explanation of Solution
Given:
The function is defined on the interval .
Calculation:
a. Graph
To solve: The function is defined on the interval ,
b. Approximate the area by Partition into four subintervals of equal length and choose as the left endpoint of each subinterval.
Answer to Problem 20AYU
b.
Explanation of Solution
Given:
The function is defined on the interval .
Calculation:
b. Partition into four subintervals of equal length 1 and choose as the left endpoint of each subinterval.
The area is approximated as
To solve: The function is defined on the interval ,
c. Approximate the area by Partition into eight subintervals of equal length and choose as the left endpoint of each subinterval.
Answer to Problem 20AYU
c.
Explanation of Solution
Given:
The function is defined on the interval .
Calculation:
c. Partition into eight subintervals of equal length and choose as the left endpoint of each subinterval.
The area is approximated as
To solve: The function is defined on the interval ,
d. Express the area as an integral.
Answer to Problem 20AYU
d.
Explanation of Solution
Given:
The function is defined on the interval .
Calculation:
d. Express the area as an integral.
The area as an integral is .
To solve: The function is defined on the interval ,
e. Use a graphing utility to approximate the integral.
Answer to Problem 20AYU
e.
Explanation of Solution
Given:
The function is defined on the interval .
Calculation:
e. Use a graphing utility to approximate the integral.
That is evaluate the integral
The value of the integral is .
so the area under the graph of from 3 to 7 is .
Chapter 14 Solutions
Precalculus Enhanced with Graphing Utilities
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