Chapter 14.3, Problem 85AYU

$R(x)=\frac{(x^3-2x^2+4x-8)}{(x^2+x-6)}$

Graph $R\left(x\right)$.

To determine

To find: The graph of $R\left(x\right)$.

Answer to Problem 85AYU

Explanation of Solution

Given:

$R\left(x\right) = \frac{x^3 - 2x^2 + 4x - 8}{x^2 + x - 6}$

Calculation:

$R\left(x\right) = \frac{x^3 - 2x^2 + 4x - 8}{x^2 + x - 6}$

$R\left(x\right) = \frac{\left(x^2 + 4\right)\left(x - 2\right)}{\left(x + 3\right)\left(x - 2\right)}$

$R\left(x\right) = \frac{x^2 + 4}{x + 3}$

Graph of $R$ is as follows: