Chapter 14.1, Problem 14AYU

To determine

To find: The limit of $\underset{x\to 0}{\lim }\frac{e^x-e^{-x}}{2}$.

Answer to Problem 14AYU

Solution:

$0$

Explanation of Solution

Given:

$\underset{x\to 0}{\lim }\frac{e^x-e^{-x}}{2}$

Calculation:

$\underset{x\to 0}{\lim }\frac{e^x-e^{-x}}{2}=\frac{e^0-e^{-0}}{2}=\frac{1-1}{2}=\frac{0}{2}=0$