Chapter 14.3, Problem 1AYU

For the function $f\left(x\right)=\{\begin{array}{l}{x}^{2}ifx\le 0\\ x+1if0<x<2\\ 5-xif2\le x\le 5\end{array}$, find $f\left(0\right)$ and $f\left(0\right)$. (pp. 100-101)

To determine

To find: $f\left(0\right)$ and $f\left(2\right)$.

Answer to Problem 1AYU

$f\left(0\right)=0;f\left(2\right)=3$

Explanation of Solution

Given:

$f\left(x\right)=x^2;x\le 0$

$f\left(x\right)=x+1;0<x<2$

$f\left(x\right)=5-x;2\le x\le 5$

Formula used:

$f\left(x\right)=x^2;x\le 0$

$f\left(x\right)=x+1;0<x<2$

$f\left(x\right)=5-x;2\le x\le 5$

Calculation:

$f\left(x\right)=x^2;x\le 0$

$f\left(0\right)=0^2=0$

$f\left(x\right)=5-x;2\le x\le 5$

$f\left(2\right)=5-2=3$