(a) Explanation Given information: The discharge ( Q ) of water is 1.2 m 3 / min . The distance between hinge and canter of gravity G as 300 mm . The combined mass ( m p ) of the vane and plate is 20 kg . Calculation: Find the mass flow rate using the relation as follows: d m d t = ρ Q (1) Here, d m d t is mass flow rate and ρ is density of water. Substitute 1.2 m 3 / min for Q and 1000 kg / m 3 for ρ in Equation (1). d m d t = ( 1000 kg m 3 ) ( 1.2 m 3 min ) ( 1 min 60 s ) = 20 kg / s Sketch the free body diagram as shown in Figure 1. Refer to Figure 1. Find the speed ( v ) of the flow by using impulse momentum principle as follows: Take a moment about C . ( Δ m ) v A a − m ρ g ( Δ t ) l cos θ = ( Δ m ) v B b v A = v B = m p g l cos θ ( a − b ) Δ m Δ t (2) Substitute 20 kg / s for Δ m Δ t , 110 mm for a , 300 mm for l , 9 (b) To determine Find the reaction at C .

VEC MECH 180-DAT EBOOK ACCESS(STAT+DYNA)

12th Edition

ISBN: 9781260916942

Author: BEER

Publisher: MCG

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Chapter 14.3, Problem 14.67P

(a)

To determine

Find the speed (v) of the flow of water.

(b)

To determine

Find the reaction at C.

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Chapter 14.3, Problem 14.66P

Chapter 14.3, Problem 14.68P

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Find the speed ( v ) of the flow of water.

Solution Summary: The author explains how to find the speed of the flow of water using the impulse momentum principle. The distance between hinge and canter of gravity is 300mm.