Fluid Mechanics Fundamentals And Applications
3rd Edition
ISBN: 9780073380322
Author: Yunus Cengel, John Cimbala
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 14, Problem 90EP
To determine
The electric power production from the plant in
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The second moments of area about z-axis, /z, and the second moments of area about y-axis, ly, can be calculated as
Select one:
O 1. I = Iz
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Iz =
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64
I₁ = D, Iz
Ly
Ly
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Iz =
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[If L=3508 mm, W-9189 N, E=80 GPa, Determine the deflection at the free end of the beam.]
Step -2
Which equation in the following choices most accurately represents the functional relationship between the value of the slope
O (Units: Radian) at half length (x = L/2) of the beam and the second moment of area about z-axis, Izz (Units: mm²), of the cross section?
(Please note that " X = L/2" is the same as "X = L ÷ 2" .)
Select one:
O 1.0 448787.925/Izz
O 2.0 279167.292/Izz
O 3.0 38871.395/Izz
O 4.0 114847.304/Izz
O 5.0 176688.160/Izz
O 6.0 609574.150/Izz
O 7.0 70675.264/Izz
Use the principle of virtual work to determine the vertical deflection and rotation at tip (Point B) of the cantilever shown below.
(L=6847 mm, q = 5331 N/mm, M = 1408549 N.mm, and El = 8.6 x 1014 N. mm²)
q
Y
M
X
A
ΕΙ
B
L
Step -1
Let the coordinates defined with origin located at B and x-axis pointing to the Left and Y-axis pointing upward. The bending moment, M (Units: N.mm), in the beam
as a function of spatial coordinate x(Units: mm) can be most accurately described by
Select one:
1. M=1126839.200 +2132.400*x*x
2. M=-1408549.000 - 3198.600*x*x
3. M=-1408549.000-2665.500*x*x
4. M=-1408549.000-2132.400*x*x
5. M= -1408549.000+2665.500*x*x
6. M= 1408549.000 + 2665.500*x*x
7. M= 1408549.000-2665.500*x*x
Chapter 14 Solutions
Fluid Mechanics Fundamentals And Applications
Ch. 14 - List at least two common examples of fans, of...Ch. 14 - What are the primary differences between fans,...Ch. 14 - Prob. 3CPCh. 14 - Explain why there is an “extra” term in the...Ch. 14 - Explain why there is an “extra” term in the...Ch. 14 - Prob. 6CPCh. 14 - Prob. 7CPCh. 14 - An air compressor increases the pressure (PoutPin)...Ch. 14 - Prob. 9PCh. 14 - Prob. 10CP
Ch. 14 - Prob. 11CPCh. 14 - Prob. 12CPCh. 14 - There are three main categories of dynamic pumps....Ch. 14 - Consider flow through a water pump. For each...Ch. 14 - Prob. 15CPCh. 14 - Prob. 16CPCh. 14 - Prob. 17CPCh. 14 - Prob. 18CPCh. 14 - Prob. 19CPCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Consider the flow system sketched in Fig....Ch. 14 - Prob. 24PCh. 14 - Repeat Prob. 14-25, but with a rough pipe-pipe...Ch. 14 - The performance data for a centrifugal water pump...Ch. 14 - Suppose the pump of Probs. 14-29 and 14-30 is used...Ch. 14 - The performance data for a centrifugal water pump...Ch. 14 - Prob. 32PCh. 14 - Prob. 34PCh. 14 - The performance data of a water pump follow the...Ch. 14 - For the application at hand, the how rate of Prob....Ch. 14 - A water pump is used to pump water from one large...Ch. 14 - For the pump and piping system of Prob. 14-35E,...Ch. 14 - A water pump is used to pump water from one large...Ch. 14 - Calculate the volume flow rate between the...Ch. 14 - Comparing the resu1t of Probs. 14—43 and 14—47,the...Ch. 14 - Repeat Prob. 14—43, but neglect all minor losses....Ch. 14 - A local ventilation system (a hood and duct...Ch. 14 - The performance data for a centrifugal water pump...Ch. 14 - Transform each column of the pump performance data...Ch. 14 - A local ventilation system (a hood and duct...Ch. 14 - For the duct system and fan of Prob. 14—55E,...Ch. 14 - Repeat Prob. 14—55E. Ignoring all minor losses....Ch. 14 - 14-51 A local ventilation system (a hood and duct...Ch. 14 - The two-lobe rotary pump of Fig. P14-63E moves...Ch. 14 - Prob. 64EPCh. 14 - Prob. 65PCh. 14 - Prob. 66PCh. 14 - A centrifugal pump rotates at n=750rpm . Water...Ch. 14 - Prob. 68PCh. 14 - Suppose the pump of Prob. I 4—67 has some reverse...Ch. 14 - Prob. 70PCh. 14 - Prob. 71PCh. 14 - Prob. 72PCh. 14 - Prob. 73CPCh. 14 - Name and briefly describe the differences between...Ch. 14 - Discuss the meaning of reverse swirl in reaction...Ch. 14 - Prob. 76CPCh. 14 - Prob. 77PCh. 14 - Prob. 78PCh. 14 - Prob. 79PCh. 14 - Prob. 80PCh. 14 - Prob. 81PCh. 14 - Wind (=1.204kg/m3) blows through a HAWT wind...Ch. 14 - Prob. 83PCh. 14 - Prob. 85PCh. 14 - Prob. 86EPCh. 14 - Prob. 88PCh. 14 - Prob. 89PCh. 14 - Prob. 90EPCh. 14 - The average wind speed at a proposed HAWT wind...Ch. 14 - Prob. 92CPCh. 14 - Prob. 93CPCh. 14 - Discuss which dimensionless pump performance...Ch. 14 - Prob. 95PCh. 14 - Prob. 96PCh. 14 - Prob. 97PCh. 14 - Prob. 98PCh. 14 - Prob. 99PCh. 14 - Prob. 100PCh. 14 - Prob. 101PCh. 14 - Prob. 102PCh. 14 - Prob. 103PCh. 14 - Prob. 104PCh. 14 - Prob. 105PCh. 14 - Prob. 106PCh. 14 - Prob. 107PCh. 14 - Prob. 108PCh. 14 - Prob. 109PCh. 14 - Prob. 110PCh. 14 - Prob. 111PCh. 14 - Prob. 112PCh. 14 - Prob. 114PCh. 14 - Prob. 115PCh. 14 - Prove that the model turbine (Prob. 14—114) and...Ch. 14 - In Prob. 14—116, we scaled up the model turbine...Ch. 14 - Prob. 118PCh. 14 - Prob. 119PCh. 14 - Prob. 120PCh. 14 - For two dynamically similar pumps, manipulate the...Ch. 14 - Prob. 122PCh. 14 - Prob. 123PCh. 14 - Prob. 124PCh. 14 - Calculate and compare the turbine specific speed...Ch. 14 - Which turbomachine is designed to deliver a very...Ch. 14 - Prob. 127PCh. 14 - Prob. 128PCh. 14 - Prob. 129PCh. 14 - Prob. 130PCh. 14 - Prob. 131PCh. 14 - Prob. 132PCh. 14 - Prob. 133PCh. 14 - Prob. 134PCh. 14 - Prob. 135PCh. 14 - Prob. 136PCh. 14 - Prob. 137PCh. 14 - The snail-shaped casing of centrifugal pumps is...Ch. 14 - Prob. 139PCh. 14 - Prob. 140PCh. 14 - Prob. 141PCh. 14 - Prob. 142PCh. 14 - Prob. 143PCh. 14 - Prob. 144PCh. 14 - Prob. 145PCh. 14 - Prob. 146PCh. 14 - Prob. 147PCh. 14 - Prob. 148PCh. 14 - Prob. 149PCh. 14 - Prob. 150PCh. 14 - Prob. 151PCh. 14 - Prob. 152P
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- Calculate the principal stress σ at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.5363.64 O 2. 12872.727 3.9118.182 4. 10727.273 5. 16090.909 6. 2681.818arrow_forwardQuestion2 The mission profile for a jet driven aircraft consists of the following segments: engine start and warm-up, taxi, take-off, climb to the cruise altitude of 35000 ft, descend to 10000 ft, one hour loiter at this altitude at 60% of the cruise speed, flight at loiter speed and altitude to an alternate airport (100 nm), descend to landing approach condition followed by the final landing, taxi and shutdown. The cruise Mach number is 0.8. No provisions are made for the reserved fuel or any trapped oil and fuel. The aircraft carries 200 people (including pilots and the cabin crew) at 175 lb each and 90 lb baggage each. This aircraft has a wing area of 2000 ft² L/D at cruise L/D at 10000ft flight Table Q2 20 16 0.43 lb/hr/lb 0.50 lb/hr/lb C: Specific Fuel Consumption at cruise: C: Specific Fuel Consumption at 10000 ft flight: Weight ratios Engine Start and warm-up Taxi Take-off Climb Descent Landing, taxi and shutdown 0.992 0.996 0.996 0.996 0.992 0.992 Question 2 continues on the…arrow_forwardCalculate the principal stress σ1_at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places. Select one: O 1.25745.455 O 2. 32181.818 3. 21454.545 4. 17163.636 5. 12872.727arrow_forward
- Calculate the Von-Mises effective stress at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.27870.272 O2. 18580.181 3. 11148.109 O 4. 14864.145 O 5.22296.218arrow_forwardA bar of length L and of a circular cross-section of diameter D is clamped at the top end and loaded at the other (bottom) end by a point load P as shown in Figure Q2a. The cross-section of the bar is shown in Figure Q2b indicating that load is applied at the point A. The material used in the bar has specific weight y. Find the magnitude and location of the maximum normal stress in the bar. Figure Q2 a Figure Q2 b 45°arrow_forwardA close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as σ = T/(2πR²t), where the mean radius of the cross section is R(i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>> t, you can approximately assume that the internal radius of the tube is equal to Rin the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T Ozz бее буг Z бее T бел Figure Q3 Centreline of the wall Rarrow_forward
- A bar of length L and of a circular cross-section of diameter D is clamped at the top end and loaded at the other (bottom) end by a point load P as shown in Figure Q2a. The cross-section of the bar is shown in Figure Q2b indicating that load is applied at the point A. The material used in the bar has specific weight y. Find the magnitude and location of the maximum normal stress in the bar. Figure Q2 a Figure Q2 b 45° Aarrow_forward(If L=3508 mm, W-9189 N, E=80 GPa, Determine the deflection at the free end of the beam.) Step-4 Which equation in the following choices most accurately represents the functional relationship between the value of the deflection, Vmax ( Units: mm) at the free end (XL) of the beam and the second moment of area about z-axis, Izz (Units: mm²) of the cross section ? (Please note that " X = L/2" is the same as "X = L ÷ 2" .) Select one: O 1. Vmax 1776823249.026 / Izz O 2. Vmax 516518386.345/Izz O 3. Vmax=743786476.336/Izz O 4. Vmax 1002045669.509/Izz O 5. Vmax 330571767.261/Izz O 6. Vmax 196276986.811 / Izz O 7. Vmax 1435921114.038/Izzarrow_forwardThe second moment of area about z-axis of the cross section, Izz ( Units: mm4) can be calculated as Select one: O 1. 2.081 x 107 ○ 2. 2.281x 107 ○ 3. 2.201 x 107 ○ 4. 1.348x 107 ○ 5. 1.466 x107 ○ 6. 1.966x107 O 7. 1.833 x 107 O 8. 1.109x 107arrow_forward
- [(a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel. (P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21)] Step-3 The functional relationship between the change of the diameter, DD (units: mm), and wall thickness t(units: mm) can be most accurately expressed as Select one: O 1. DD-282.688/t O 2. DD=424.033/t O 3. DD=343.447/t 4. DD = 686.894/t O 5. DD=1696.130/t O 6. DD-228.965/t 7. DD=848.065/t 8. DD=1373.789/tarrow_forwardA bar of length L and of a circular cross-section of diameter D is clamped at the top end and loaded at the other (bottom) end by a point load P as shown in Figure Q2a. The cross-section of the bar is shown in Figure Q2b indicating that load is applied at the point A. The material used in the bar has specific weight y. Find the magnitude and location of the maximum normal stress in the bar. Z Figure Q2 a Figure Q2 b 45° Aarrow_forwardA close end tube of thin-walled circular section may be subjected to torque Tand internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²t), where the mean radius of the cross section is R(i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>>t, you can approximately assume that the internal radius of the tube is equal to Rin the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. T Centreline of the wall R P Ozz бөө Orr Z бут бее Ozz Figure Q3 (a) If the change of the diameter cannot exceed 0.1 m under elastic deformation, calculate the minimum allowable wall thickness of the cylindrical pressure vessel if P=23.6 MPa, T=0 KN.m, R = 2 m, Young's modulus E = 246 GPa, and Poisson's ratio v = 0.21. Step-1 the functional relationships between hoop stress σ and wall thickness…arrow_forward
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