Explanation Given data: The required diagram is drawn as shown in figure 1. Calculation: The conversion of mF into F is done as, 1 mF = 1 × 10 − 3 F Hence, the conversion of 333 mF into F is, 333 mF = 333 × 10 − 3 F = 0.333 F The required diagram for the s domain circuit is drawn as shown in figure 2. From the above figure it is observed that there is a series combination of resistance and capacitance that is in parallel with the series combination of inductance and resistance. The input impedance is calculated as, Z ( s ) = ( 1.5 + 1 0.333 s ) ∥ ( 1.7 s + 4.7 ) = ( 1.5 + 1 0.333 s ) ( 1.7 s + 4.7 ) ( 1.5 + 1 0.333 s ) + ( 1.7 s + 4.7 ) = ( 0.4995 s + 1 0.333 s ) ( 1.7 s + 4.7 ) ( 0.4995 s + 1 + 0.566 s 2 + 1.5651 s 0.333 s ) = 0.84915 s 2 + 1.7 s + 2.34765 s + 4.7 0.566 s 2 + 0.4995 s + 1.565 s + 1 Further simplify the above expression. Z ( s ) = 0.8915 ( s 2 + 4.766 s + 5.5349 ) 0.5661 ( s 2 + 3.6470 s + 1

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Chapter 14, Problem 74E

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The poles and zeros of Y(s).

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Chapter 14, Problem 73E

Chapter 14, Problem 75E

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