Chapter 14, Problem 5P

Given this set of daily service operations, and assuming a processing order of A-B -C-D-E:

a. Give one reason that each arrangement might be preferred over the other.

b. Determine the number of repetitions for each service if four cycles are used.

c. Determine the number of repetitions for each service if two cycles are used.

Summary Introduction

To determine: Reason each arrangement might be preferred over the other.

Introduction: A production cycle is a period through which the objects of labor like raw materials and goods stay in the creation procedure from the earliest starting point of assembling through the yield of completed item. Additionally the working time, the creation cycle incorporates interferences underway inferable from physical, synthetic, and organic forms or the character of the objects of work or the innovation and association of generation.

Explanation of Solution

Given Information:

Process order: A-B-C-D-E

Service Operation	Number of Daily Reps
A	22
B	12
C	4
D	18
E	8

The following are the reasons each arrangement might be preferred over the other:

• Two cycles have low amounts of substitutions.
• Four cycles have low inventory and are considered as high on suppleness.

Summary Introduction

To determine: The number of repetitions for each service if four cycles used.

Introduction: A production cycle is a period through which the objects of labor like raw materials and goods stay in the creation procedure from the earliest starting point of assembling through the yield of completed item. Additionally the working time, the creation cycle incorporates interferences underway inferable from physical, synthetic, and organic forms or the character of the objects of work or the innovation and association of generation.

Answer to Problem 5P

The number of repetitions for service operation A is 5.5, B is 3, C is 1, D is 4.5 and E is 2.

Explanation of Solution

Calculate the number of repetitions for each service if four cycles used.

It is calculated by dividing each product’s daily quantity by 4.

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}A}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; A}}_{}}{4}\right]\\ =\left[\frac{22}{4}\right]\\ =5.5\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}B}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; B}}_{}}{4}\right]\\ =\left[\frac{12}{4}\right]\\ =3\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}C}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; C}}_{}}{4}\right]\\ =\left[\frac{4}{4}\right]\\ =1\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}D}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; D}}_{}}{4}\right]\\ =\left[\frac{18}{4}\right]\\ =4.5\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}E}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; E}}_{}}{4}\right]\\ =\left[\frac{8}{4}\right]\\ =2\end{array}$

Hence the number of repetitions for service operation A is 5.5, B is 3, C is 1, D is 4.5 and E is 2.

Determine the processing order if four cycles used.

Cycle	1	2	3	4
A	6	6	5	5
B	3	3	3	3
C	1	1	1	1
D	4	4	5	5
E	2	2	2	2

Summary Introduction

To determine: The number of repetitions for each service if two cycles used.

Introduction: A production cycle is a period through which the objects of labor like raw materials and goods stay in the creation procedure from the earliest starting point of assembling through the yield of completed item. Additionally the working time, the creation cycle incorporates interferences underway inferable from physical, synthetic, and organic forms or the character of the objects of work or the innovation and association of generation.

Answer to Problem 5P

The number of repetitions for service operation A is 11, B is 6, C is 2, D is 9 and E is 4.

Explanation of Solution

Calculate the number of repetitions for each service if two cycles used.

It is calculated by dividing each product’s daily quantity by 2.

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}A}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; A}}_{}}{2}\right]\\ =\left[\frac{22}{2}\right]\\ =11\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}B}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; B}}_{}}{2}\right]\\ =\left[\frac{12}{2}\right]\\ =6\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}C}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; C}}_{}}{2}\right]\\ =\left[\frac{4}{2}\right]\\ =2\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}D}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; D}}_{}}{2}\right]\\ =\left[\frac{18}{2}\right]\\ =9\end{array}$

$\begin{array}{c}\mathrm{Number}\mathrm{of}\mathrm{Reps}\mathrm{per}{\mathrm{Cycle}}_{\mathrm{Service}\mathrm{Operation}\text{\hspace{0.17em}E}}=\left[\frac{\mathrm{Service}{\mathrm{Operation\; E}}_{}}{2}\right]\\ =\left[\frac{8}{2}\right]\\ =4\end{array}$

Hence the number of repetitions for service operation A is 11, B is 6, C is 2, D is 9 and E is 4.

Determine the processing order if two cycles used.

Cycle	1	2
A	11	11
B	6	6
C	2	2
D	9	9
E	4	4