
Concept explainers
(a)
Interpretation:
The dehydrated product formed from the following alcohol with
Concept Introduction:
A
In a chemical reaction, the substance which is involved in conversion is said to be a reactant, whereas the newly formed substance is known as a product. Both reactants and products must be separated by an arrow.
A dehydration reaction is an elimination reaction in which a water molecule eliminates from alcohol to form

Answer to Problem 58P
Explanation of Solution
To get the dehydrated product of any alcohol, three steps must be followed:
- Locate the C atom in the parent chain that is bonded with −OH group.
- Eliminate H and OH group from two adjacent C's
- Add a double bond between these C's to form the product alkene.
- If there is a possibility to form two or more alkene, the major product has more C's bonded to the C=C. This is known as the Zaitsev rule.
Hence, the dehydration of 4-methylpentanol will form 4-methyl-1-pentene molecule.
(b)
Interpretation:
The dehydrate product formed from the following alcohol with
Concept Introduction:
A chemical reaction is the symbolic representation of the conversion of substances to new substances.
In a chemical reaction, the substance which is involved in conversion is said to be reactant whereas the newly formed substance is known as a product. Both reactants and products must be separated by an arrow.
A dehydration reaction is an elimination reaction in which a water molecule eliminates from alcohol to form alkene in the presence of

Answer to Problem 58P
Explanation of Solution
To get the dehydrated product of any alcohol, three steps must be followed;
- Locate the C atom in the parent chain that is bonded with −OH group.
- Eliminate H and OH group from two adjacent C's
- Add a double bond between these C's to form the product alkene.
- If there is a possibility to form two or more alkene, the major product has more C's bonded to the C=C. This is known as the Zaitsev rule.
Hence, the dehydration of given alcohol will form only one alkene as all H next to −OH are the same.
(c)
Interpretation:
The dehydrated product formed from the following alcohol with
Concept Introduction:
A chemical reaction is the symbolic representation of the conversion of substances to new substances.
In a chemical reaction; the substance which is involved in conversion is said to be reactant whereas the newly formed substance is known as a product. Both reactants and products must be separated by an arrow.
A dehydration reaction is an elimination reaction in which a water molecule eliminates from alcohol to form alkene in the presence of

Answer to Problem 58P
Explanation of Solution
To get the dehydrated product of any alcohol, three steps must be followed:
- Locate the C atom in the parent chain that is bonded with −OH group.
- Eliminate H and OH groups from two adjacent C's.
- Add a double bond between these C's to form the product alkene.
- If there is a possibility to form two or more alkene, the major product has more C's bonded to the C=C. This is known as the Zaitsev rule.
Hence, the dehydration of 2-octanol can form two alkenes as both the neighbor C of OH group have H atoms. Hence, dehydration of 2-octanol will follow Zaitsev rule and will form 2-octene as the major product and 1-octene as a minor product as 2-octene is more substituted alkene than 1-octene.
(d)
Interpretation:
The dehydrate product formed from the following alcohol with
Concept Introduction:
A chemical reaction is the symbolic representation of the conversion of substances to new substances.
In a chemical reaction; the substance which is involved in conversion is said to be reactant whereas the newly formed substance is known as a product. Both reactants and products must be separated by an arrow.
A dehydration reaction is an elimination reaction in which a water molecule eliminates from alcohol to form alkene in the presence of

Answer to Problem 58P
Explanation of Solution
To get the dehydrated product of any alcohol, three steps must be followed:
- Locate the C atom in the parent chain that is bonded with −OH group.
- Eliminate H and OH group from two adjacent C's
- Add a double bond between these C's to form the product alkene.
- If there is a possibility to form two or more alkene, the major product has more C's bonded to the C=C. This is known as the Zaitsev rule.
Hence the dehydration of given alcohol can form two alkenes as both the neighbor C of OH group have H atoms. Hence dehydration of 1-methylcyclopentanol will follow Zaitsev rule and will form 1-methylcyclpentene as the major product and methylenecyclopentane as a minor product, as 1-methylcyclpentene is more substituted alkene than methylenecyclopentane.
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Chapter 14 Solutions
General, Organic, and Biological Chemistry - 4th edition
- Indicate the products obtained by mixing 2,2-dimethylpropanal with acetaldehyde and sodium ethoxide in ethanol.arrow_forwardSynthesize 2-Ethyl-3-methyloxirane from dimethyl(propyl)sulfonium iodide using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize 2-Hydroxy-2-phenylacetonitrile from phenylmethanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forward
- Synthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardIf possible, please provide the formula of the compound 3,3-dimethylbut-2-enal.arrow_forward
- Synthesize 1,4-dibromobenzene from acetanilide (N-phenylacetamide) using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardIndicate the products obtained by mixing (3-oxo-3-phenylpropyl)triphenylphosphonium bromide with sodium hydride.arrow_forwardWe mix N-ethyl-2-hexanamine with excess methyl iodide and followed by heating with aqueous Ag2O. Indicate the major products obtained.arrow_forward
- Indicate the products obtained by mixing acetophenone with iodine and NaOH.arrow_forwardIndicate the products obtained by mixing 2-Propanone and ethyllithium and performing a subsequent acid hydrolysis.arrow_forwardIndicate the products obtained if (E)-2-butenal and 3-oxo-butanenitrile are mixed with sodium ethoxide in ethanol.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
