Different isotopes (versions) of the same element can have very different half-lives. With t in years, the decay of plutonium-240 is described by the formula Q = Q 0 e − 0.00011 t , whereas the decay of plutonium-242 is described by Q = Q 0 e − 0.0000018 t . Find the half-lives of plutonium-240 and plutonium-242.
Different isotopes (versions) of the same element can have very different half-lives. With t in years, the decay of plutonium-240 is described by the formula Q = Q 0 e − 0.00011 t , whereas the decay of plutonium-242 is described by Q = Q 0 e − 0.0000018 t . Find the half-lives of plutonium-240 and plutonium-242.
Different isotopes (versions) of the same element can have very different half-lives. With t in years, the decay of plutonium-240 is described by the formula
Q
=
Q
0
e
−
0.00011
t
,
whereas the decay of plutonium-242 is described by
Q
=
Q
0
e
−
0.0000018
t
.
Find the half-lives of plutonium-240 and plutonium-242.
Determine whether the lines
L₁ (t) = (-2,3, −1)t + (0,2,-3) and
L2 p(s) = (2, −3, 1)s + (-10, 17, -8)
intersect. If they do, find the point of intersection.
Convert the line given by the parametric equations y(t)
Enter the symmetric equations in alphabetic order.
(x(t)
= -4+6t
= 3-t
(z(t)
=
5-7t
to symmetric equations.
Find the point at which the line (t) = (4, -5,-4)+t(-2, -1,5) intersects the xy plane.
Elementary and Intermediate Algebra: Concepts and Applications (7th Edition)
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