EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 14, Problem 32QTP
Take two solid, cylindrical specimens of equal diameter, but different heights, and compress them (frictionless) to the same percent reduction in height. Show that the final diameters will be the same.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A 10 mm thick plate is rolled to 7 mm thick in a rolling mill using 1000 mm diameter rigid rolls. The neutral point is located at an angle of 0.3 times the bite angle from the exit. What will be the thickness of the plate at the neutral point.
A solid, cylindrical workpiece made of 5052-O aluminum that is 87 mm high and 65.878 mm radius and is to be reduced in height by 30% using forging. The coefficient of friction is 0.168. 5052-O yield stress is 98.21 MPa, strain hardening exponent is 0.128 , and strength coefficient is 193.74 MPa.
Determine the forging force (MN) at the end of the stroke when the height has been reduced by 30%.
5) A steel specimen of rectangular cross section with 120 mm width, 180 mm
thickness and 90 mm height was upset at room temperature by open-die forging to
a height of 55 mm. If the strength coefficient and strain hardening exponent of this
material were 1015 MPa and 0.17 respectively, the coefficient of friction is 0.2, and
assuming that the thickness would not change during forging; determine the
required upsetting force at the end of stroke.
Chapter 14 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 14 - What is the difference between cold, warm, and hot...Ch. 14 - Explain the difference between open-die and...Ch. 14 - Explain the difference between fullering, edging,...Ch. 14 - What is flash? What is its function?Ch. 14 - Why is the intermediate shape of a part important...Ch. 14 - Describe the features of a typical forging die.Ch. 14 - Explain what is meant by load limited, energy...Ch. 14 - What type of parts can be produced by rotary...Ch. 14 - Why is hubbing an attractive alternative to...Ch. 14 - What is the difference between piercing and...
Ch. 14 - What is a hammer? What are the different kinds of...Ch. 14 - Why is there barreling in upsetting?Ch. 14 - What are the advantages and disadvantages of...Ch. 14 - Why are draft angles required in forging dies?Ch. 14 - Is a mandrel needed in swaging?Ch. 14 - Describe and explain the factors that influence...Ch. 14 - How can you tell whether a certain part is forged...Ch. 14 - Identify casting design rules, described in...Ch. 14 - Describe the factors involved in precision...Ch. 14 - Why is control of the volume of the blank...Ch. 14 - Why are there so many types of forging machines...Ch. 14 - What are the advantages and limitations of cogging...Ch. 14 - What are the advantages and limitations of using...Ch. 14 - Review Fig. 14.6e and explain why internal draft...Ch. 14 - Comment on your observations regarding the...Ch. 14 - Describe your observations concerning the control...Ch. 14 - Prob. 27QLPCh. 14 - Describe the difficulties involved in defining the...Ch. 14 - Describe the advantages of servo presses for...Ch. 14 - List the general recommendations you would make...Ch. 14 - Which would you recommend, (a) hot forging and...Ch. 14 - Take two solid, cylindrical specimens of equal...Ch. 14 - Calculate the room-temperature forging force for a...Ch. 14 - Using Eq. (14.2), estimate the forging force for...Ch. 14 - To what thickness can a solid cylinder of 1020...Ch. 14 - In Example 14.1, calculate the forging force,...Ch. 14 - Using Eq. (14.1), make a plot of the forging...Ch. 14 - How would you go about estimating the punch force...Ch. 14 - A mechanical press is powered by a 30-hp motor and...Ch. 14 - A solid cylindrical specimen, made of a perfectly...Ch. 14 - Devise an experimental method whereby you can...Ch. 14 - Assume that you represent the forging industry and...Ch. 14 - Figure P14.44 shows a round impression-die forging...Ch. 14 - Prob. 45SDPCh. 14 - Prob. 46SDPCh. 14 - Review the sequence of operations in the...Ch. 14 - Prob. 48SDPCh. 14 - Discuss the possible environmental concerns...Ch. 14 - List the advantages and disadvantages in using a...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A long, copper strip, 500 mm wide, 3 mm thick, was found to have 450 MPa yield stress. The strip is required to be rolled in order to reduce its thickness. In the rolling process, the width remains practically unchanged while the rolls apply pressure in the thickness direction. An additional tension of 150 kN is applied in the longitudinal direction to assist the forming process. Ignoring the change in the width and any friction effects, determine what roll pressure would just cause deformation: according to the Von Mises yield criterion. according to the Tresca yield criterion. Material properties in the elastic range: E=75 GPa, v=0.4. (a) (b)arrow_forwardThe team performs a cold heading operation to produce the head on a steel nail. The strength coefficient for this steel is K = 550 MPa, and the strain hardening exponent n = 0.24. Coefficient of friction at the die- work interface = 0.10. The wire stock out of which the nail is made is 4.75 mm in diameter. The head is to have a diameter = 9.5 mm and a thickness = 1.5 mm. (a) What length of stock must project out of the die in order to provide sufficient volume of material for this upsetting operation? (b) Compute the maximum force that the punch must apply to form the head in this open-die operation. Discuss the result?arrow_forwardA spool of copper wire has a starting diameter of 2.5 mm. It is drawn through a die with an opening that is 2.1 mm. The entrance angle of the die = 18°. Coefficient of friction at the work die interface is 0.08. The pure copper has a strength coefficient = 300 MPa and a strain hardening coefficient = 0.50. The operation is performed at room temperature. Determine (a) area reduction, (b) draw stress, and (c) draw force required for the operation.arrow_forward
- A billet 100 mm long and 40 mm diameter is to be extruded in a direct extrusion with final diameter of product 32 mm. The semi die angle is 60°. The work metal has a strength coefficient 500 Map, and strain hardening 0.2 use the Johnson formula with a=0.8 and b=1.45 to estimate the extrusion strain. Determine the pressure applied to the end of the billet as the ram moves forward.arrow_forwardIn a stamping operation, a 2 mm thick stainless steel sheet with an ultimate tensile strenght of 900 MPa is used. For a given blank size of 200 mm x 200 mm, calculate the punching force required to make a sheet metal part with 20 circle holes, each 4 mm and 10 square holes each with an edge of 5 mm. (1)arrow_forwardA compound die will be used to blank and punch a large washer out of 6061ST aluminum alloy sheet stock 4.50 mm thick. The outside diameter of the washer is 60.0 mm and the inside diameter is 25.0 mm. Determine the punch and die sizes for the blanking operation. Determine the force required to perform the blanking and punching operation, assuming that the punches are staggered so that punching occurs first, then blanking. The aluminum sheet metal has a tensile strength = 310 MPa. Consider a clearance allowance value of 0.060.arrow_forward
- A 300mm thick slab is being cold rolled using roll of 600mm diameter.If the coefficient of friction is 0.08. Determine the maximum possible reduction.arrow_forwardA cylindrical part with initial diameter of 45 mm and the initial height of 40 mm is upset forged in an open die to a height = 25 mm. The strength coefficient is 650 MPa and strain- hardening exponent is 0.12. Qa =1.11 (Qa takes into account both friction and workpiece geometry). Calculate the force required for upsetting this part at room temperature. O 1786 kN O 1648 kN O 1247 kN O 1109 kN O none of themarrow_forwardWire is drawn through a draw die with entrance angle a= 17°. Starting diameter is 3.0 mm and final diameter = 2.4 mm. The coefficient of friction at the work-die interface = 0.08. The metal has a strength coefficient K = 205 MPa and a strain-hardening exponent n = draw force in this operation. Why are multiple passes usually required to achieve the desired reduction? (Hint: Observe the draw stress value found in this question) 0.20. Determine the draw stress and Lubricant box Initial wire stock (in coil form) Multiple pass/draft drawing Draw die V2, F V3, F shown in figure. Capstan drum (holds multiple loops of wire) (1) (2) (3)arrow_forward
- A steel billet with a rectangular cross section is being forged using a die with a width of 84.5 mm. The billet has an original thickness of 46.0 mm and a width of 273 mm. The billet is upset to a thickness of 28.0 mm and the coefficient of friction for the workpiece-die interface is 0.234. Take the strength coefficient (K) as 526 MPa and the strain-hardening exponent (n) as 0.225. a) Determine the maximum die pressure (do not use average pressure formula). Expected answer: 1050 MPa b) Determine the required forging force (use average pressure). Expected answer: 16200000 Narrow_forward0/ Two thick slabs of 300mm each, the first one is used in cold rolling where μ=0.08 while the second is used in cold rolling where µ-0.5. The mill roll diameter in each case is the same as 600mm. Determine the max draft (reduction) in both cases. Discuss the wide difference in results.arrow_forwardIn a slab rolling operation, the maximum thickness reduction (del hmax) is given by del hmax = μ²R, where R is the radius of the roll and u is the coefficient of friction between the roll and the sheet. If µ = 0.1, find the maximum angle subtended by the deformation zone at the centre of the roll.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Types of Manufacturing Process | Manufacturing Processes; Author: Magic Marks;https://www.youtube.com/watch?v=koULXptaBTs;License: Standard Youtube License