Essential Organic Chemistry, Global Edition
3rd Edition
ISBN: 9781292089034
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Question
Chapter 14, Problem 20P
Interpretation Introduction
Interpretation:
The value for the relative east of removing a hydrogen atom from tertiary, secondary and primary hydrogen carbons by a chlorine radical has to be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Chlorine radical forms a tertiary radical five times faster than a primary radical and it forms a secondary radical 3.8 times faster than a primary radical.
Relative rates of alkyl radical formation by a chlorine radical at 125 °C.
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When exactly 1 mole of methane is mixed with exactly 1 mole of chlorine and light is shone on the mixture, a chlorination reaction occurs. The products are found to contain substantial amounts of di-, tri-, and tetrachloromethane, as well as unreacted methane. Explain how a mixture is formed from this stoichiometric mixture of reactants, and propose mechanisms for the formation of these compounds from chloromethane.
Free‑radical halogenation can occur with chlorine and a source of direct UV radiation or sunlight. Chlorination of 2,4‑dimethylpentane via radical halogenation leads to the formation of all three of the products shown. Estimate the relative percentages of each product that will be formed using this means of halogenation. Presume that 1 equivalent of chlorine is used.
Define the Mechanism of the Radical Addition of HBr to an Alkene ?
Chapter 14 Solutions
Essential Organic Chemistry, Global Edition
Ch. 14.2 - Write the mechanism for the monobromination of...Ch. 14.2 - Prob. 2PCh. 14.4 - Prob. 3PCh. 14.4 - Which of the hydrogens in the structure in the...Ch. 14.4 - How many alkyl chlorides can be obtained from...Ch. 14.4 - Prob. 7PCh. 14.5 - Prob. 9PCh. 14.6 - a. Which ether is most apt to form a peroxide? b....Ch. 14.7 - Prob. 11PCh. 14 - Prob. 12P
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